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Worked Example of Percentage Yield Calculations: Calculating Percentage Yield
Question: 112 g of nitrogen gas reacts with hydrogen gas to produce 40.8 g of ammonia gas according to the equation given below:
N2(g) + 3H2(g) ⇋ 2NH3(g)
Calculate the percentage yield of ammonia.
Solution:
- Actual yield is the mass of ammonia that is actually produced during the chemical reaction.
Actual yield of ammonia (NH3) = 40.8 g (given in the question)
- Theoretical yield of ammonia (NH3) is the mass of product predicted by the balanced chemical equation for the reaction.
From the balanced chemical equation the mole ratio (stoichiometric ratio) N2:NH3 is 1:2
therefore: moles NH3 = 2 × moles N2
Assuming ALL the available N2 reacts completely, then the maximum amount of NH3 that can be produced is:
moles NH3 = 2 × (mass N2 ÷ molar mass N2) = 2 × (112 ÷ [2 × 14]) = 2 × (112 ÷ 28) = 8 mol
Theoretical yield NH3 = predicted mass NH3
Predicted mass NH3 = maximum mass of NH3 that can be produced assuming that ALL the N2 reacts completely:
mass(NH3) = moles(NH3) × molar mass(NH3)
predicted mass NH3 = 8 × (14 + 3 × 1) = 8 × 17 = 136 g
Theoretical yield = predicted mass = 136 g
- Percentage yield = (actual yield ÷ theoretical yield) × 100
Substituting the vales for actual yield and theoretical yield into the equation:
percentage yield NH3 = (40.8 ÷ 136) × 100 = 30%
Worked Example of Percentage Yield Calculations: Calculating Mass of Product from Yield
Question: Ammonia can be produced from hydrogen gas and nitrogen gas according to the equation below:
N2(g) + 3H2(g) ⇋ 2NH3(g)
Calculate the mass of ammonia produced if 168 g of nitrogen gas produces a yield of 45%.
Solution:
- percentage yield = (actual yield ÷ theoretical yield) × 100
Percentage yield = 45% (given in question)
percentage yield = (actual yield ÷ theoretical yield) × 100 = 45%
- Calculate the theoretical yield of NH3 (the mass of NH3 produced as predicted by the balanced chemical equation for the reaction)
From the balanced chemical equation the mole ratio (stoichiometric ratio) N2:NH3 is 1:2
therefore moles NH3 = 2 × moles N2
Assuming ALL the available N2 reacts completely, then the maximum amount of NH3 that can be produced is:
moles NH3 = 2 × (mass N2 ÷ molar mass N2) = 2 × (168 ÷ [2 × 14]) = 2 × (168 ÷ 28) = 12 moles
theoretical yield NH3 = predicted mass NH3
Predicted mass NH3 = maximum mass of NH3 that can be produced assuming that ALL the N2 reacts completely:
mass(NH3) = moles(NH3) × molar mass(NH3)
predicted mass NH3 = moles NH3 × molar mass NH3 = 12 × (14 + 3 × 1) = 12 × 17 = 204 g
theoretical yield NH3 = predicted mass NH3 = 204 g
- Calculate the actual yield:
percentage yield = (actual yield ÷ theoretical yield) × 100
Re-arranging this equation gives:
actual yield = theoretical yield × (percentage yield ÷ 100)
Substituting the values for percentage yield and theoretical yield into this equation:
actual yield of NH3 = 204 × (45 ÷ 100) = 91.8 g
Factors Affecting Actual Yield
Le Chatelier's Principle can be used to predict the affect of changes in temperature, concentration, gas pressure and volume on actual yield as summarised in the table below:
Factor |
Conditions |
Actual Yield |
% Yield |
reactant concentration increase |
|
increases |
increases |
|
reactant concentration decrease |
|
decreases |
decreases |
|
temperature increase |
exothermic reaction |
decreases |
decreases |
endothermic reaction |
increases |
increases |
|
temperature decrease |
exothermic reaction |
increases |
increases |
endothermic reaction |
decreases |
decreases |
|
gas pressure increase |
mol reactant(gas) > mol product(gas) |
increases |
increases |
mol reactant(gas) < mol product(gas) |
decreases |
decreases |
|
gas pressure decrease |
mol reactant(gas) > mol product(gas) |
decreases |
decreases |
mol reactant(gas) < mol product(gas) |
increases |
increases |
Note that if a change to the equilibrium system results in an increase in the actual yield of product then the percentage yield of that product must also increase.
Likewise, if a change to the equilibrium system results in an decrease in the actual yield of product then the percentage yield of that product must also decrease.