Periodic Table: Trends Across Period 2 Chemistry Tutorial
Key Concepts
- The horizontal rows of the periodic table are called periods.
- Period 2, or the second period, refers to the second row from the top of the periodic table.
- The elements in period 2 of the periodic table are:
Name of Element |
lithium |
beryllium |
boron |
carbon |
nitrogen |
oxygen |
fluorine |
neon |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
- The following general trends are observed as you go across period 2 from left to right:
(a) atomic number, and therefore charge on the nucleus (nuclear or core charge) increases
(b) number of valence electrons increases
(c) atomic radius decreases
(d) first ionisation energy increases
(f) electronegativity increases (excluding neon)
(g) elements on the left are metals, elements on the right are non-metals:
(i) melting points change from high to low
(ii) electrical and heat conductors on the left to insulators on the right
(iii) metallic lustre on the left to dull on the right
(iv) halides change from ionic on the left to covalent on the right
(v) oxides change from ionic and basic on the left to covalent and acidic on the right
- The general trends in the properties of period 2 elements is summarized in the table below:
Trends in Properties of Period 2 Elements |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Metallic Character |
metals |
→ |
semi-metal |
→ |
non-metals |
Bond Type |
metallic |
→ |
covalent |
Melting Point |
high |
→ |
low |
Conductivity |
high |
→ |
low |
Lustre |
metallic |
→ |
dull |
Atomic Radius |
high |
→ |
low |
1st Ionisation Energy |
low |
→ |
high |
Electronegativity |
low |
→ |
high |
Atomic Number |
low |
→ |
high |
No. electrons |
low |
→ |
high |
Ions of Elements |
cations |
→ |
anions |
Halides of Elements |
ionic |
→ |
covalent |
|
Oxides of Elements |
basic |
→ amphoteric → |
acidic |
|
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Properties of Elements in Period 2 of the Periodic Table
The table below gives a number of different properties of the elements of period 2 of the periodic table.
Can you see any patterns, or trends, in the data?
Name of Element (Symbol) |
Lithium (Li) |
Beryllium (Be) |
Boron (B) |
Carbon (C) |
Nitrogen (N) |
Oxygen (O) |
Fluorine (F) |
Neon (Ne) |
Atomic Number (z) |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
Electronic Configuration |
2,1 |
2,2 |
2,3 |
2,4 |
2,5 |
2,6 |
2,7 |
2,8 |
Atomic Radius (pm) |
152 |
112 |
88 |
77 |
70 |
66 |
68 |
67 |
1stIonization Energy (kJ mol-1) |
526 |
905 |
810 |
1090 |
1410 |
1320 |
1690 |
2090 |
Electronegativity (Pauling) |
0.98 |
1.57 |
2.04 |
2.55 |
3.04 |
3.44 |
3.98 |
|
Melting Point (°C) |
180 |
1280 |
2027 |
graphite 3272 diamond > 3700 |
-210 |
-219 |
-187 |
-248.6 |
Boiling Point (°C) |
1330 |
2480 |
3900 |
graphite 4827 diamond |
-196 |
-183 |
-188 |
-246.1 |
Electrical Conductance (mho) |
excellent 105 |
good 5.4 × 105 |
poor 2 × 10-5 |
graphite good diamond no |
no |
no |
no |
Lustre |
metallic |
metallic |
metallic |
graphite faint metallic diamond brilliant |
dull |
dull |
dull |
Metallic Character |
metal |
metal |
semi-metal (metalloid) |
non-metal |
non-metal |
non-metal |
non-metal |
non-metal |
Physical Properties of Period 2 Elements
Elements to the left of period 2 are metals, those to the right are non-metals.
Metals usually have higher melting and boiling points than non-metals, so let's examine the melting points of period 2 elements:
Name of Element |
lithium |
beryllium |
boron |
carbon (graphite) |
nitrogen |
oxygen |
fluorine |
neon |
Melting Point (°C) |
180 |
1280 |
2027 |
3272 |
-210 |
-219 |
-187 |
-248.6 |
The elements on the right, nitrogen, oxygen, fluorine and neon all have low melting points and are all non-metals.
In fact, apart from neon which exists as a monatomic gas (Ne(g)) at room temperature and pressure, the others are all diatomic gases, nitrogen gas (N2(g)), oxygen gas (O2(g)) and fluorine gas (F2(g)).
Only weak intermolecular forces (London forces or dispersion forces) act between these covalent molecules, so little energy is required to disrupt the attraction and melt the solid, or indeed, boil the liquid to produce a gas.
The elements on the left, lithium and beryllium have high melting points and are metals.
Strong metallic bonds hold the "atoms" in a 3-dimensional array and it requires a lot of energy to disrupt these attractive forces so the melting points are high.
The melting point of boron is very high, so is it a metal? ,
Boron has other properties such as being a semiconductor, not a metallic conductor which place it in the borderline region between being a metal and a nonmetal so we shall classify it as a semi-metal (or metalloid).
What about the high melting point of carbon, is carbon a metal?
Carbon has other properties that make it definitely a non-metal, such as the formation of covalent bonds between carbon atoms which produce large (infinite) 3-dimensional lattices that make graphite and diamond (see allotropes).
It requires a lot of energy to disrupt these strong covalent bonds holding the carbon atoms in place in the lattice so the melting point of carbon (either as graphite or diamond) is high.
So, we see a trend from high to low melting points across period 2 from left to right, a trend from solid to gas, as well as a trend from metal to semi-metal to non-metal, and a trend from metallic bonds to covalent network solid to diatomic molecules to monatomic gas:
Name of Element |
lithium |
beryllium |
boron |
carbon (graphite) |
nitrogen |
oxygen |
fluorine |
neon |
State (25°C, 100 kPa) |
solid |
solid |
solid |
solid |
gas |
gas |
gas |
gas |
Chemical Formula (25°C, 100 kPa) |
Li(s) |
Be(s) |
B(s) |
C(s) |
N2(g) |
O2(g) |
F2(g) |
Ne(g) |
Classification of Element |
metal |
metal |
semi-metal |
non-metal |
non-metal |
non-metal |
non-metal |
non-metal |
Intramolecular Forces |
metallic bonds |
metallic bonds |
covalent bonds |
covalent bonds |
covalent bonds |
covalent bonds |
covalent bonds |
not applicable |
Intermolecular Forces |
metallic bonds |
metallic bonds |
covalent bonds |
covalent bonds |
London forces |
London forces |
London forces |
London forces |
We can also look at the conductivity of period 2 elements to confirm the same trend: metallic to semi-metal (metalloid) to non-metal:
Name of Element |
lithium |
beryllium |
boron |
carbon (graphite) |
nitrogen |
oxygen |
fluorine |
neon |
Electrical Conductivity (mho) |
105 (excellent) |
5.4 × 105 (excellent) |
2 × 10-5 (poor) |
graphite: good diamond: insulator |
insulator |
insulator |
insulator |
insulator |
The delocalised electrons in the structure of a metal allows metals to conduct electricity well. Lithium and beryllium are metals.
At room temperature, boron is a poor conductor of electricity, but its conductivity increases when it is heated. Boron is a semi-metal (or metalloid).
The delocalised electrons between the carbon layers of graphite allow electricity to be conducted in this way, but the electrons are "locked up" in covalents bonds in the diamond structure so diamonds do not conduct electricity, diamond is an insulator.
Similarly, there are no mobile electrons to conduct electricity in the structure of the other non-metals.
The trend from conductor to poor conductor to insulator across period 2 from left to right confirms the trend from metal to semi-metal (metalloid) to non-metal.
Atomic Structure of Period 2 Elements
Consider the atomic number of each period 2 element :
Name of Element |
lithium |
beryllium |
boron |
carbon |
nitrogen |
oxygen |
fluorine |
neon |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Atomic Number (Z) |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
Trend in atomic number |
low |
→ |
→ |
→ |
→ |
→ |
→ |
high |
The modern periodic table is arranged in order of increasing atomic number (Z) from left to right across a period.
This means that a proton is added to the nucleus of each atom of each successive member of period 2.
Since each proton carries a charge of 1+, we say that the charge on the nucleus is increasing across the period, or that the nuclear charge is increasing, or that the core charge is increasing across the period.
Remember that an atom has no overall charge, so the total positive charge on the nucleus due to the protons must equal the total negative charge resulting from the electrons.
For an atom of each element the number of protons = the number of electrons.
Name of Element |
lithium |
beryllium |
boron |
carbon |
nitrogen |
oxygen |
fluorine |
neon |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Atomic Number (Z) |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
Number of Electrons |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
Trend in number of electrons |
low |
→ |
→ |
→ |
→ |
→ |
→ |
high |
But how are those electrons arranged arround the nucleus of each atom?
Each atom of each element in period 2 has a filled K shell (or first energy level), that is, each of atoms has 2 electrons in the K shell.
Each subsequent electron is positioned in the L shell, or second energy level.
With the group 18 element neon, Ne, this second energy level (L shell) is complete.
Name of Element |
lithium |
beryllium |
boron |
carbon |
nitrogen |
oxygen |
fluorine |
neon |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Number of Electrons |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
Electronic Configuration |
2,1 |
2,2 |
2,3 |
2,4 |
2,5 |
2,6 |
2,7 |
2,8 |
Trend in electronic configuration |
low |
→ |
→ |
→ |
→ |
→ |
→ |
high |
As electrons are added to the same energy level (shell) across the period, the increasingly large positive charge on the nucleus pulls these electrons closer so that the size of the atoms decrease across the period from left to right.
We measure the size of an atom by its atomic radius:
Name of Element |
lithium |
beryllium |
boron |
carbon |
nitrogen |
oxygen |
fluorine |
neon |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Electronic Configuration |
2,1 |
2,2 |
2,3 |
2,4 |
2,5 |
2,6 |
2,7 |
2,8 |
Atomic Radius (pm) |
152 |
112 |
88 |
77 |
70 |
66 |
68 |
67 |
Trend in atomic radius |
large |
← |
← |
← |
← |
← |
← |
small |
Since the valence electrons (those electrons in the highest energy level) are more strongly attracted to the nucleus, they will be more difficult to remove.
We have evidence to support this idea from an inspection of the values for the first ionisation energy of element (the energy required to remove an electron from the gaseous atom to form a gaseous cation);
Name of Element |
lithium |
beryllium |
boron |
carbon |
nitrogen |
oxygen |
fluorine |
neon |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Electronic Configuration |
2,1 |
2,2 |
2,3 |
2,4 |
2,5 |
2,6 |
2,7 |
2,8 |
Atomic Radius (pm) |
152 |
112 |
88 |
77 |
70 |
66 |
68 |
67 |
First Ionisation Energy (kJ mol-1) |
526 |
905 |
810 |
1090 |
1410 |
1320 |
1690 |
2090 |
General Trend in 1st Ionisation Energy |
small |
→ → → → → → |
large |
In general, the energy required to remove an electron from each atom in period 2 increases as you go from left to right across the period. (1)
This suggests that elements on the left hand side of the period 2 are more likely to form positive ions, that is lose an electron, than elements on the right hand side of period 2.
If we consider the ability of an atom of each period 2 element to attract elctrons towards itself (its electronegativity) we would expect the elements on the right which have a smaller atomic radius and greater nuclear charge to be better at this than those atoms on the left hand side of the period.
This trend of increasing electronegativity across period 2 from left to right is shown in the table below:
Name of Element |
lithium |
beryllium |
boron |
carbon |
nitrogen |
oxygen |
fluorine |
neon |
Chemical Symbol |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Electronic Configuration |
2,1 |
2,2 |
2,3 |
2,4 |
2,5 |
2,6 |
2,7 |
2,8 |
Atomic Radius (pm) |
152 |
112 |
88 |
77 |
70 |
66 |
68 |
67 |
Electronegativity (Pauling) |
0.98 |
1.57 |
2.04 |
2.55 |
3.04 |
3.44 |
3.98 |
|
General Trend in Electronegativity |
small |
→ → → → → → |
large |
|
This suggests that the elements on the right hand side of period 2 (exclusing neon) are more likely to gain electrons and form negative ions (anions) than those on the left hand side of period 2.
Chemical Properties of Period 2 Elements
With the exception of neon, period 2 elements react in order to achieve a stable "octet" of electrons in their valence shells.
Neon is an exception because, being a group 18 (Noble Gas) element, it already has a stable electronic configuration.
The other period 2 elements can achieve a stable octet of electrons by
- a transfer of electrons from one species to another resulting in the formation of ions and ionic bonds
- sharing of valence electrons resulting in covalent bonds
Electrons will only be transferred from one atom to another if there is a large difference in electronegativities of the two atoms.
Otherwise the valence electrons will be shared and a covalent bond formed between the atoms.
Consider how each element could form an ion with a stable electronic configuration:
Period 2 Element |
Li |
Be |
B |
C |
N |
O |
F |
Ne |
Electronic Configuration of Atom |
2,1 |
2,2 |
2,3 |
2,4 |
2,5 |
2,6 |
2,7 |
2,8 |
Electrons lost (-) or gained (+) |
-1 |
-2 |
-3 |
-4 +4 |
+3 |
+2 |
+1 |
0 |
Electronic Configuration of Ion |
2 |
2 |
2 |
2 2,8 |
2,8 |
2,8 |
2,8 |
|
Formula of Ion |
Li+ |
Be2+ |
B3+ |
C4+ C4- |
N3- |
O2- |
F- |
|
Let's consider chemical reactions that produce the halide of each element in period 2:
Period 2 Element |
Li(s) |
Be(s) |
B(s) |
C(s) |
N2(g) |
O2(g) |
F2(g) |
Ne(g) |
produces |
↓ |
↓ |
↓ |
↓ |
↓ |
↓ |
↓ |
↓ |
halides |
LiCl |
BeCl2 |
BCl3 |
CCl4 |
NCl3 |
Cl2O |
Cl2F |
no reaction |
Lithium chloride, LiCl, is an ionic compound composed of lithium cations (Li+) and chloride anions (Cl-).
The difference in electronegativity between lithium and chlorine is:
electronegativity chlorine - electronegativity lithium = 3.16 - 0.98 = 2.18
2.18 > 1.7 therefore bond is ionic
We can calculate the difference in electonegativities between each period 2 element and chlorine to determine whether the resulting halide is ionic or covalent:
Period 2 Element |
Li(s) |
Be(s) |
B(s) |
C(s) |
N2(g) |
O2(g) |
F2(g) |
Ne(g) |
halides |
LiCl |
BeCl2 |
BCl3 |
CCl4 |
NCl3 |
Cl2O |
Cl2F |
no reaction |
Difference in Electronegativities |
3.16 - 0.98 = 2.18 |
3.16 - 1.57 = 1.59 |
3.16 - 2.04 = 1.12 |
3.16 - 2.55 = 0.61 |
3.16 - 3.04 = 0.12 |
3.44 - 3.16 = 0.28 |
3.98 - 3.16 = 0.82 |
|
bond type |
ionic (> 1.7) |
covalent (< 1.7) |
covalent (< 1.7) |
covalent (< 1.7) |
covalent (< 1.7) |
covalent (< 1.7) |
covalent (< 1.7) |
|
Across period 2 from left to right the bonding in the halides changes from ionic to covalent.
Let's consider an oxidation reaction for each period 2 element to produce an oxide of each element:
Period 2 Element |
Li(s) |
Be(s) |
B(s) |
C(s) |
N2(g) |
O2(g) |
F2(g) |
Ne(g) |
oxides |
Li2O |
BeO |
B2O3 |
CO, CO2 |
NO, NO2, N2O, N2O3, N2O4, N2O5 |
|
OF2, O2F2 |
no reaction |
Now we can consider the difference in electronegativity between each period 2 element and oxygen in order to decide if each oxide is ionic or covalent:
Period 2 Element |
Li(s) |
Be(s) |
B(s) |
C(s) |
N2(g) |
O2(g) |
F2(g) |
Ne(g) |
oxides |
Li2O |
BeO |
B2O3 |
CO, CO2 |
NO, NO2, N2O, N2O3, N2O4, N2O5 |
|
OF2, O2F2 |
no reaction |
difference in electronegtivity with oxygen |
3.44 - 0.98 = 2.46 |
3.44 - 1.57 = 1.87 |
3.44 - 2.04 = 1.40 |
3.44 - 2.55 = 0.89 |
3.44 - 3.04 = 0.40 |
|
3.98 - 3.44 = 0.54 |
no reaction |
bond type |
ionic > 1.7 |
ionic > 1.7 |
covalent < 1.7 |
covalent < 1.7 |
covalent < 1.7 |
|
covalent < 1.7 |
no reaction |
Once again we see a trend across period 2 from left to right, the oxides change from being ionic to being covalent.
If we were to dissolve each oxide in water, we would find another interesting trend.
Aqueous solutions of the oxides of elements on the left are basic, then become amphoteric, while the oxides of the non-metals on the right hand side are usually acidic:
Period 2 Element |
Li(s) |
Be(s) |
B(s) |
C(s) |
N2(g) |
O2(g) |
F2(g) |
Ne(g) |
acidity of oxides |
basic |
amphoteric |
amphoteric |
CO2 acidic (CO neutral) |
NO2 acidic (NO, N2O, neutral) |
|
acidic |
|
Problem Solving
Question: Chris the Chemist has been given a sealed specimen jar containing a sample of a period 2 element.
The black solid is a good conductor of electricity.
When burnt in oxygen the sample produces a gas.
When this gas is dissolved in water, the solution turns blue litmus paper red.
Name the sample in the sample jar.
|
STOP |
STOP! State the Question.
|
|
What is the question asking you to do?
Name the period 2 element.
|
PAUSE |
PAUSE to Prepare a Game Plan
|
|
(1) What information (data) have you been given in the question?
The sample is a period 2 element
Physical properties of the element:
(a) Physical appearance at room temperature and pressure: black solid
(b) Electrical conductivity: good
Chemical properties of the element:
(a) Combustion product is a gas
(b) Aqueous solution of combustion product turns blue limus red
(2) What is the relationship between what you know and what you need to find out?
The period 2 elements are: lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine and neon.
Trends in physical properties across period 2 from left to right:
(a) solids to gases
(b) good conductors to insulators
Trends in chemical properties across period 2 from left to right:
(a) solid ionic oxides to gaseous covalent oxides (except for neon which does not form an oxide)
(b) basic aqueous solution of oxides to amphoteric to acidic
|
GO |
GO with the Game Plan |
|
Trends in physical properties across period 2 from left to right:
(a) solids to gases:
black solid should be positioned on the left of period 2
Possibilities are: lithium, beryllium, boron or carbon as graphite
(Note: lithium and beryllium less likely because their metallic lustre should have been noted)
(b) good conductors to insulators:
sample conducts so should be positioned to the left of period 2
Possibilities are: lithium, beryllium, or carbon as graphite
(Not boron which is only a poor conductor).
Trends in chemical properties across period 2 from left to right:
(a) solid ionic oxides to gaseous covalent oxides:
Sample produces a gaseous oxide, so should be positioned to the right of period 2.
Possibilities: carbon as graphite (combustion producing carbon dioxide gas), nitrogen, fluorine
(Not lithium or beryllium which would produce solid ionic oxides, not neon which is not reactive at room temperature and pressure)
(b) basic aqueous solution of oxides to amphoteric to acidic
Possibilities: oxides of carbon, nitrogen or fluorine
(Not oxides of lithium or beryllium which produce basic aqueous solutions)
This is a sample of carbon.
(Note: you have been asked to name the element, that is carbon, not the allotrope which is graphite, nor have you been asked for the symbol of the element which is C.)
|
PAUSE |
PAUSE to Ponder Plausibility |
|
Is your answer plausible?
Consider the properties of carbon to see whether it is likely to be contained in the sample jar:
Property |
Predicted for graphite |
Observed in sample |
Colour |
black |
black |
State (25°C, 100 kPa) |
solid |
solid |
Electrical Conductivity |
good (between carbon layers) |
good |
Oxide State |
gas (covalent molecule) |
gas |
Acidity of Aqueous Solution of Oxide |
acidic (CO2(g) in water) |
acidic |
Since the predicted properties of carbon as graphite agree with the properties observed in the sample, we are reasonably confident that the sample in the jar is carbon (as graphite).
|
STOP |
STOP! State the Solution |
|
The sample in the jar is carbon.
|