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Classification of Haloalkanes (alkyl halides) Chemistry Tutorial

Key Concepts

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Halomethanes (Methyl Halides)

When a halogen atom, X, replaces one of the hydrogen atoms of a methane molecule (CH4) the result is a haloalkane (CH3X).

The halomethanes (methyl halides) are given in the table below:

Name fluoromethane
(methyl fluoride)
chloromethane
(methyl chloride)
bromomethane
(methyl bromide)
iodomethane
(methyl iodide)
Structural Formula
  H
|
 
H− C −F
  |
H
 
  H
|
 
H− C −Cl
  |
H
 
  H
|
 
H− C −Br
  |
H
 
  H
|
 
H− C −I
  |
H
 
Molecular Formula CH3F CH3Cl CH3Br CH3I

Primary Haloalkanes (Primary Alkyl Halides)

One alkyl group is bonded to the head carbon, that is, the halogen atom (X) is bonded to the last carbon atom of the carbon chain.

The general formula for a primary haloalkane (1° alkyl halide) is R-CH2X where R is an alkyl chain and X is the halogen atom.

Some examples of primary chloroalkanes (1° alkyl chlorides) are given in the table below:

Name Structural Formula Condensed Structural Formula Molecular Formula
chloroethane
  H
|
  H
|
 
H− C C −Cl
  |
H
  |
H
 
CH3CH2Cl C2H5Cl
1-chloropropane
  H
|
  H
|
  H
|
 
H− C C C −Cl
  |
H
  |
H
  |
H
 
CH3CH2CH2Cl C3H7Cl
1-chlorobutane
  H
|
  H
|
  H
|
  H
|
 
H− C C C C −Cl
  |
H
  |
H
  |
H
  |
H
 
CH3[CH2]2CH2Cl C4H9Cl

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Secondary Haloalkanes (Secondary Alkyl Halides)

Two alkyl groups are bonded to the head carbon.

The halogen atom is bonded to a carbon atom that is not at the end of the chain, and this carbon atom is also bonded to a hydrogen atom.

The general formula for a secondary haloalkane (2° alkyl halide) is R-CHX-R' where R and R' are alkyl groups and X represents a halogen atom.

Some examples of secondary bromoalkanes (2° alkyl bromides) are given in the table below:

Name Structural Formula Condensed Structural Formula Molecular Formula
2-bromopropane
  H
|
  Br
|
  H
|
 
H− C C C −H
  |
H
  |
H
  |
H
 
CH3CHBrCH3 C3H7Br
2-bromobutane
  H
|
  H
|
  Br
|
  H
|
 
H− C C C C −H
  |
H
  |
H
  |
H
  |
H
 
CH3CH2CHBrCH3 C4H9Br
2-bromopentane
  H
|
  H
|
  H
|
  Br
|
  H
|
 
H− C C C C C −H
  |
H
  |
H
  |
H
  |
H
  |
H
 
CH3[CH2]2CHBrCH3 C5H11Br
3-bromopentane
  H
|
  H
|
  Br
|
  H
|
  H
|
 
H− C C C C C −H
  |
H
  |
H
  |
H
  |
H
  |
H
 
[CH3CH2]2CHBr C5H11Br

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Tertiary Haloalkanes (Tertiary Alkyl Halides)

Three alkyl groups are bonded to the head carbon.

The halogen atom is bonded to a carbon atom that is itself bonded to 3 other carbon atoms.

The general formula for a tertiary haloalkane (3° alkyl halide) is R-C[R']X-C" where R, R' and R" are alkyl groups and X is the halogen atom.

Some examples of tertiary fluoroalkanes (3° alkyl fluorides) are given in the table below:

Name Structural Formula Condensed Structural Formula Molecular Formula
2-fluoro-2-methylpropane
  H
|
  F
|
  H
|
 
H− C C C −H
  |
H
|
H-C-H
|
H
 
      |
H
     
[CH3]3CF C4H9F
2-fluoro-2-methylbutane
  H
|
  F
|
  H
|
  H
|
 
H− C C C C −H
  |
H
|
H-C-H
|
H
  |
H
 
      |
H
         
[CH3]2CFCH2CH3 C5H11F
3-fluoro-3-methylpentane
  H
|
  H
|
  F
|
  H
|
  H
|
 
H− C C C C C −H
  |
H
  |
H
|
H-C-H
|
H
  |
H
 
          |
H
         
CH3CF[CH2CH3]2 C6H13F

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Footnotes:

(1) The use of "haloalkanes" refers to the use of IUPAC substitutive nomenclature to name these compounds, wheres the use of "alkyl halides" refers to the use of IUPAC functional class nomenclature to name these compounds. The use of "halogenoalkane" is a non-systematic nomenclature. The IUPAC recommendation is for substitutive nomenclature so "haloalkane" is preferred to "halogenoalkane" (non-systematic) or "alkyl halide".
The rules for naming organic compounds are still being developed. The most recent document for referral is "Preferred names in the nomenclature of organic compounds" (Draft 7 October 2004).

(2) Halides are good leaving groups so it is actually the structure of the alkyl parts of the haloalkane molecules that is more important because this determines the stability of any carbocation (carbonium ion) formed, and determines the steric hindrance of a concerted reaction, neither of which will be discussed in this introductory tutorial.

(3) Other factors are also very important in determining the ratio of substitution vs elimination products, for example, the strength of the base, the nature of the solvent, and the temperature.