Steps for IUPAC Naming of Straight-Chain Haloalkanes (alkyl halides)
The systematic IUPAC name for a straight-chain haloalkane is made up of a prefix and a stem.
halo |
alkane |
prefix |
stem name |
The stem is determined by the number of carbon atoms making up the longest carbon chain (which includes the halogen atoms that have substituted for hydrogen atoms).
The prefix is determined by the number and type of halogen atoms that occur along the parent alkane chain (the longest carbon chain).
Step 1: Identify and name the longest carbon chain containing the halogen atoms.
Name the carbon chain as you would for an alkane molecule:
Number of Carbon atoms in the chain |
1 |
2 |
3 |
4 |
5 |
|
7 |
8 |
9 |
10 |
stem (parent alkane) |
methane |
ethane |
propane |
butane |
pentane |
hexane |
heptane |
octane |
nonane |
decane |
Step 2: Identify and name each halogen atom present in the molecule:
Symbol of Element |
Name of Element |
"Halo" Prefix to use |
F |
fluorine |
fluoro |
Cl |
chlorine |
chloro |
Br |
bromine |
bromo |
I |
iodine |
iodo |
Step 3: If more than one type of halogen atom is present, list the halo prefixes in ascending alphabetical order from left to right:
order written |
first |
second |
third |
fourth |
prefix |
bromo |
chloro |
fluoro |
iodo |
Step 4: If more than one atom of the same halogen element is present, modify the halo prefix using the appropriate multiplier prefix:
Number of identical halogen atoms |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
multiplier prefix |
di |
tri |
tetra |
penta |
hexa |
hepta |
octa |
Step 5: Add the multiplier prefix to the name of the halogen atom as written in the order given in Step 3 above.
If only one atom of a particular halogen atom is present, no multiplier is included for this atom.
DO NOT change the order!
order written |
first |
second |
third |
fourth |
modified prefix |
multiplierbromo |
multiplierchloro |
multiplierfluoro |
multiplieriodo |
Step 6: Number the carbon atoms in the parent alkane chain so that the halogen atoms are attached to the carbon atoms with the lowest set of numbers.
The lowest set of numbers is that which, when compared term by term in the order given above, has the lowest term at the first point of difference.
Example: 1-bromo-2-chloroethane NOT 2-bromo-1-chloroethane
Step 7: Use the number of the carbon atom to which each halogen is attached as an infix for that modified prefix.
Note: The modified prefix representing each halogen atom must be preceded by a number.
If the modified prefix does not include a multiplier (that is only one atom of this halogen element is present), one number will precede the prefix.
If the modified prefix includes a multipler prefix, then the number of numbers is the same as indicated by the multiplier prefix
di means there must be two numbers preceding the prefix, tri means there must be three numbers preceding the prefix, etc
Note, numbers for each halogen atom are written in ascending order.
Numbers making each infix are separated from each other by a comma (,)
Numbers making up each infix are separated from words (or word fragments) by hyphens (-)
order written |
first |
second |
third |
fourth |
infix-modified prefix |
infix-multiplierbromo |
infix-multiplierchloro |
infix-multiplierfluoro |
infix-multiplieriodo |
Step 8: Assemble the final name.
Write the out the string of infix-multiplierhalo prefixes in alphabetical order with a hyphen (-) between word fragments and numbers:
infix-multiplierbromo-infix-multiplierchloro-infix-multiplierfluoro-infix-multiplieriodo
Write the name of the parent alkane (determined in Step 1 above) directly after the last halogen element's prefix.
DO NOT leave a space between the name of the halogen prefix and the alkane's name.
infix-multiplierbromo-infix-multiplierchloro-infix-multiplierfluoro-infix-multiplieriodoalkane
Worked Example: IUPAC Naming of Haloalkane with a Single Substitution
Name the haloalkane molecule shown below using systematic IUPAC nomenclature rules:
| | H | | H | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Cl |
| | | | | | | | | | |
| | H | | H | | H | | |
Step 1: Identify and name the longest carbon chain containing the halogen atoms.
| | H | | H | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Cl |
| | | | | | | | | | |
| | H | | H | | H | | |
Longest carbon chain has 3 carbon atoms.
propane is the name of the alkane with 3 carbon atoms.
Stem = propane
Step 2: Identify and name each halogen atom present in the molecule:
| | H | | H | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Cl |
| | | | | | | | | | |
| | H | | H | | H | | |
Cl is the symbol for the halogen element chlorine.
prefix is chloro
Step 3: If more than one type of halogen atom is present, list the halo prefixes in ascending alphabetical order from left to right:
Only one type of halogen atom is present, that is, just chlorine.
prefix is still chloro
Step 4: If more than one atom of the same halogen element is present, modify the halo prefix using the appropriate multiplier prefix:
Only one chlorine atom is present.
prefix is still chloro
Step 5: Add the multiplier prefix to the name of the halogen atom as written in the order given in Step 3 above.
No multiplier prefix is required because only one atom of chlorine is present.
prefix is still chloro
Step 6: Number the carbon atoms in the parent alkane chain so that the halogen atoms are attached to the carbon atoms with the lowest set of numbers
numbering from left to right |
|
numbering from right to left |
| | H | | H | | H | | |
| | | | | | | | | | |
H | - | C1 | - | C2 | - | C3 | - | Cl |
| | | | | | | | | | |
| | H | | H | | H | | |
|
|
| | H | | H | | H | | |
| | | | | | | | | | |
H | - | C3 | - | C2 | - | C1 | - | Cl |
| | | | | | | | | | |
| | H | | H | | H | | |
|
Numbering from right to left results in the chlorine atom being attached carbon 1 rather than carbon 3 (as when the chain is numbered from left to right).
The preferred numbering is therefore from right to left because it results in the lowest number for the infix.
Step 7: Use the number of the carbon atom to which each halogen is attached as an infix for that modified prefix.
chlorine atom attached to carbon 1 :
infix-prefix is 1-chloro
Step 8: Assemble the final name: add the prefix to the name of the parent alkane
1-chloropropane
Worked Example: IUPAC Naming of Haloalkane with Multiple Substitutions of the Same Halogen
Name the haloalkane molecule shown below using systematic IUPAC nomenclature rules:
| | H | | Br | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
Step 1: Identify and name the longest carbon chain containing the halogen atoms.
| | H | | Br | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
Longest carbon chain has 3 carbon atoms.
propane is the name of the alkane with 3 carbon atoms.
Stem = propane
Step 2: Identify and name each halogen atom present in the molecule:
| | H | | Br | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
Br is the symbol for the halogen element bromine.
prefix is bromo
Step 3: If more than one type of halogen atom is present, list the halo prefixes in ascending alphabetical order from left to right:
Only one type of halogen atom is present, that is, just bromine.
prefix is still bromo
Step 4: If more than one atom of the same halogen element is present, modify the halo prefix using the appropriate multiplier prefix:
Three bromine atoms are present.
multiplier prefix is tri
Step 5: Add the multiplier prefix to the name of the halogen atom as written in the order given in Step 3 above.
multiplier prefix is tri
modified bromo prefix is now tribromo
Step 6: Number the carbon atoms in the parent alkane chain so that the halogen atoms are attached to the carbon atoms with the lowest set of numbers
numbering from left to right |
|
numbering from right to left |
| | H | | Br | | H | | |
| | | | | | | | | | |
H | - | C1 | - | C2 | - | C3 | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
|
|
| | H | | Br | | H | | |
| | | | | | | | | | |
H | - | C3 | - | C2 | - | C1 | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
|
Br attached to carbons 2,2,3 |
|
Br attached to carbons 1,2,2 |
The preferred numbering is from right to left because it results in the lowest set of numbers for the infix (1,2,2 instead of 2,2,3).
Step 7: Use the number of the carbon atom to which each halogen is attached as an infix for that modified prefix.
bromine atoms attached to carbons 1,2,2
infix-prefix is 1,2,2-tribromo
Step 8: Assemble the final name: add the prefix to the name of the parent alkane
1,2,2-tribromopropane
Worked Example: IUPAC Name of Haloalkane With Substitution by More Than One Type of Halogen Atom
Name the haloalkane molecule shown below using systematic IUPAC nomenclature:
| | H | | Cl | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
Step 1: Identify and name the longest carbon chain containing the halogen atoms.
| | H | | Cl | | H | | |
| | | | | | | | | | |
H | - | C | - | C | - | C | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
Longest carbon chain has 3 carbon atoms.
propane is the name of the alkane with 3 carbon atoms.
Stem = propane
Step 2: Identify and name each halogen atom present in the molecule:
Cl is the symbol for chlorine, modified name to be used in the prefix is chloro
Br is the symbol for bromine, modified name to be used in the prefix is bromo
Step 3: If more than one type of halogen atom is present, list the halo prefixes in ascending alphabetical order from left to right:
bromo chloro
("b" from bromo comes before "c" from chloro in the alphabet)
Step 4: If more than one atom of the same halogen element is present, modify the halo prefix using the appropriate multiplier prefix:
two bromine atoms, multiplier to use is di
one chlorine atom, no multiplier is used
Step 5: Add the multiplier prefix to the name of the halogen atom as written in the order given in Step 3 above.
dibromo chloro
Step 6: Number the carbon atoms in the parent alkane chain so that the halogen atoms are attached to the carbon atoms with the lowest set of numbers
numbering from left to right |
|
numbering from right to left |
| | H | | Cl | | H | | |
| | | | | | | | | | |
H | - | C1 | - | C2 | - | C3 | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
|
|
| | H | | Cl | | H | | |
| | | | | | | | | | |
H | - | C3 | - | C2 | - | C1 | - | Br |
| | | | | | | | | | |
| | H | | Br | | H | | |
|
Br attached to carbons 2 and 3 (infix 2,3-) Cl atom attached to carbon 2 (infix 2-) |
|
Br attached to carbons 1 and 2 (infix 1,2-) Cl atom attached to carbon 2 (infix 2-) |
The preferred numbering is from right to left because it results in the lowest set of numbers for the infixes.
That is infex 1,2 for bromine atoms and 2 for chlorine atom (rather than 2,3 for bromine and 2 for chlorine)
Step 7: Use the number of the carbon atom to which each halogen is attached as an infix for that modified prefix.
Remember, numbers are separated from numbers by commas, numbers are separated from letters by hyphens, and, there are no spaces!
1,2-dibromo-2-chloro
Step 8: Assemble the final name: add the prefix to the name of the parent alkane
Remember there are no spaces in the final name!
1,2-dibromo-2-chloropropane
Steps for Drawing the Structure(4) of Straight Chain Haloalkanes
Step 1: Break the name of the haloalkane up into two parts: prefix and stem (the name of the parent alkane)
halo |
alkane |
prefix |
stem name |
Step 2: Determine the number of carbon atoms in the parent alkane from the stem.
Step 3: Draw the parent alkane showing all carbon atoms and covalent bonds.
Remember that there are only single covalent bonds between the carbon atoms in an alkane molecule.
Do not show hydrogen nor halogen atoms.
Step 4: Break the prefix of the haloalkane's name up into "infix-multiplierhalo" segments.
Step 5: Determine the number and type of each halogen atom present using each "multiplierhalo" segment.
Step 6: Determine the location of each halogen atom using the infix for each segment.
Step 7: Number the carbon atoms in this parent alkane molecule in ascending order from left to right.
Step 8: Position each halogen atom along the chain in the location indicated by the infix for each segment.
Step 9: Complete the structure by placing a hydrogen atom (H) at the end of any vacant covalent bond.
Worked Example of Drawing the Structure of a Haloalkane (alkyl halide)
Draw the structure for 1,2-dibromo-1-chloro-1-fluoroethane
Step 1: Break the name of the haloalkane up into two parts: prefix and stem (the name of the parent alkane)
1,2-dibromo-1-chloro-1-fluoro |
ethane |
prefix |
stem name |
Step 2: Determine the number of carbon atoms in the parent alkane from the stem.
stem is ethane (name of the parent alkane)
eth = 2 carbon atoms
Step 3: Draw the parent alkane showing all carbon atoms and covalent bonds.
Remember that there are only single covalent bonds between the carbon atoms in an alkane molecule.
Do not show hydrogen nor halogen atoms.
Step 4: Break the prefix of the haloalkane's name up into "infix-multiplierhalo" segments.
There are three "infix-multiplierhalo" segments in the name of this molecule:
(i) 1,2-dibromo
(ii) 1-chloro
(iii) 1-fluoro
Step 5: Determine the number and type of each halogen atom present using each "multiplierhalo" segment.
(i) 1,2-dibromo = two Br atoms (di multiplier = two atoms of this halogen)
(ii) 1-chloro = one Cl atom (no multiplier means there is only one atom of this halogen)
(iii) 1-fluoro = one F atom (no multiplier means there is only one atom of this halogen)
Step 6: Determine the location of each halogen atom using the infix for each segment.
(i) 1,2-dibromo : one Br atom is located on carbon 1, one Br atom is located on carbon 2
(ii) 1-chloro : one Cl atom is located on carbon 1
(iii) 1-fluoro : one F atom is located on carbon 1
Step 7: Number the carbon atoms in this parent alkane molecule in ascending order from left to right.
Step 8: Position each halogen atom along the chain in the location indicated by the infix for each segment.
|
Cl |
|
|
|
|
| |
|
| |
|
Br- |
C1 |
- |
C2 |
-Br |
|
| |
|
| |
|
|
F |
|
|
|
Step 9: Complete the structure by placing a hydrogen atom (H) at the end of any vacant covalent bond.
|
Cl |
|
H |
|
|
| |
|
| |
|
Br- |
C |
- |
C |
-Br |
|
| |
|
| |
|
|
F |
|
H |
|