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Mole Fraction and Mole Percent

Key Concepts

Mole Fraction

Mole Percent

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Example: Calculating Mole Fraction of Solute and Solvent

Question: What is the mole fraction and mole percent of sodium chloride and the mole fraction and mole percent of water in an aqueous solution containing 25.0 g water and 5.0 g sodium chloride?

Solution:

  1. Identify the components making up the solution:
    solute = sodium chloride = NaCl
    solvent = water = H2O (because this is an aqueous solution)
  2. Write the equation for finding the mole fraction of solute:
    Χ(NaCl) = n(NaCl) ÷ (n(NaCl) + n(H2O))
  3. Calculate the moles of each component:

    moles of solute (NaCl):
    n(NaCl) = mass ÷ molar mass
    mass (NaCl) = 5.0 g
    molar mass (NaCl) = 22.99 + 35.45 = 58.44 g mol-1
    n (NaCl) = 5.0 ÷ 58.44 = 0.08556 mol
    moles of solvent (H2O):
    n(H2O) = mass ÷ molar mass
    mass (H2O) = 25.0 g
    molar mass (H2O) = 2 × 1.008 + 16.00 = 18.016 g mol-1
    n (H2O) = 25.0 ÷ 18.016 = 1.3877 mol

  4. Calculate the mole fraction of sodium chloride:
    Χ(NaCl) = n(NaCl) ÷ (n(NaCl) + n(H2O))
    Χ(NaCl) = 0.08556 ÷ (0.08556 + 1.3877)
    Χ(NaCl) = 0.058
  5. Calculate mole percent of NaCl:
    mole percent of NaCl = 100 × Χ(NaCl)
    mole percent of NaCl= 100 × 0.058
    mole percent of NaCl= 5.8%
  6. Write the equation for finding the mole fraction of solvent:
    Χ(H2O) = 1 - Χ(NaCl)
  7. Calculate the mole fraction of solvent (water):
    mole fraction of solvent (water) = 1 - Χ(NaCl)
    mole fraction of solvent (water) = 1 - 0.058
    mole fraction of solvent (water) = 0.942
  8. Calculate mole percent of H2O
    mole percent of H2O = 100 × Χ(H2O)
    mole percent of H2O = 100 × 0.942
    mole percent of H2O = 94.2%

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Example: Calculating Mass of Solute or Solvent

Question: A particular aqueous solution contains 7.5 moles of water and a mole fraction of sodium chloride of 0.125.
How many grams of sodium chloride are present in the solution?

Solution:

  1. Re-arrange the equation Χ(NaCl) = n(NaCl) ÷ (n(NaCl) + n(H2O)) to find n(NaCl):
    Multiply both sides by (n(NaCl) + n(H2O)):

    Χ(NaCl) × (n(NaCl) + n(H2O)) = n(NaCl)

    Expand the expression on the left hand side:

    (NaCl) × n(NaCl)) + (Χ(NaCl) × n(H2O)) = n(NaCl)

    Collect like terms (n(NaCl)):

    Χ(NaCl) × n(H2O) = n(NaCl) - (Χ(NaCl) × n(NaCl))

    Re-arrange the expression for n(NaCl)

    Χ(NaCl) × n(H2O) = n(NaCl)(1 - Χ(NaCl))

    Divide throughout by (1 - Χ(NaCl)) to get an expression for n(NaCl):

    (NaCl) × n(H2O)) ÷ (1 - Χ(NaCl)) = n(NaCl)

  2. Calculate moles of NaCl:
    n(NaCl) = (Χ(NaCl) × n(H2O)) ÷ (1 - Χ(NaCl))
    n(NaCl) = (0.125 × 7.5) ÷ (1 - 0.125)
    n(NaCl) = 1.071 mol
  3. Calculate mass of NaCl:
    n(NaCl) = mass(NaCl) ÷ molar mass(NaCl)
    mass(NaCl) = n(NaCl) × molar mass(NaCl)
    mass(NaCl) = 1.071 × 58.44
    mass(NaCl) = 62.6 g

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