Mass-Action Expressions (Q) Chemistry Tutorial
Key Concepts
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Writing the Mass-Action Expression, Q
By agreement, reactants are defined as on the left of a chemical equation and products on the right:
reactants |
⇋ |
products |
aA |
+ |
bB |
⇋ |
cC |
+ |
dD |
Each term used in the mass-action expression, Q, is the concentration of the species raised to the power of its stoichiometric coefficient:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
aA |
+ |
bB |
⇋ |
cC |
+ |
dD |
term for each species |
[A]a |
|
[B]b |
|
[C]c |
|
[D]d |
The mass-action expression, Q, is written in the form:
Q = |
numerator denominator |
By general agreement:
- the numerator of the mass-action expression (above the line) contains the product terms multiplied together
- the denominator of the mass-action expression (below the line) contains the reactant terms multiplied together
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
aA |
+ |
bB |
⇋ |
cC |
+ |
dD |
term for each species |
[A]a |
|
[B]b |
|
[C]c |
|
[D]d |
numerator term |
|
[C]c[D]d |
denominator term |
[A]a[B]b |
|
mass-action expression, Q = |
numerator denominator |
= |
[C]c[D]d [A]a[B]b |
Worked Example: Reaction in Gas Phase
Question: Write the mass-action expression for the following reaction:
2CO2(g) ⇋ 2CO(g) + O2(g)
Step 1: Determine which are the products and which are reactants for this reaction:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
2CO2(g) |
⇋ |
2CO(g) |
+ |
1O2(g) |
Remember: if there is no number in front of the chemical formula for a particular species in the equation, then it is understood that the stoichiometric coefficient is in fact 1.
Step 2: Write a term for each species in the form of its concentration raised to the power of its stoichiometric coefficient:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
2CO2(g) |
⇋ |
2CO(g) |
+ |
1O2(g) |
terms for each species: |
[CO2(g)]2 |
|
[CO(g)]2 |
|
[O2(g)]1 |
Note: any number raised to the power of 1 is simply equal to that number, that is, 21 = 2, 10561 = 1056, etc
So, [O2(g)]1 = [O2(g)]
Step 3: Write the term for the numerator by multiplying together the terms for each product:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
2CO2(g) |
⇋ |
2CO(g) |
+ |
1O2(g) |
terms for each species: |
[CO2(g)]2 |
|
[CO(g)]2 |
|
[O2(g)]1 |
numerator term |
|
|
[CO(g)]2[O2(g)] |
Step 4: Write the term for the denominator by multiplying together the terms for each reactant:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
2CO2(g) |
⇋ |
2CO(g) |
+ |
1O2(g) |
terms for each species: |
[CO2(g)]2 |
|
[CO(g)]2 |
|
[O2(g)]1 |
numerator term |
|
|
[CO(g)]2[O2(g)] |
denominator term: |
[CO2(g)]2 |
|
|
|
|
Step 5: Write the mass-action expression, Q, by dividing the numerator by the denominator:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
2CO2(g) |
⇋ |
2CO(g) |
+ |
1O2(g) |
terms for each species: |
[CO2(g)]2 |
|
[CO(g)]2 |
|
[O2(g)]1 |
numerator term |
|
|
[CO(g)]2[O2(g)] |
denominator term: |
[CO2(g)]2 |
|
|
|
|
mass-action expression, Q = |
numerator denominator |
= |
[CO(g)]2[O2(g)] [CO2(g)]2 |
Worked Example: Reaction in Aqueous Solution
Question: Write the mass-action expression for the following reaction:
Fe3+(aq) + SCN-(aq) ⇋ Fe(SCN)2+(aq)
Step 1: Determine which are the products and which are reactants for this reaction:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
1Fe3+(aq) |
+ |
1SCN-(aq) |
⇋ |
1Fe(SCN)2+(aq) |
Remember: if there is no number in front of the chemical formula for a particular species in the equation, then it is understood that the stoichiometric coefficient is in fact 1.
Step 2: Write a term for each species in the form of its concentration raised to the power of its stoichiometric coefficient:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
1Fe3+(aq) |
+ |
1SCN-(aq) |
⇋ |
1Fe(SCN)2+(aq) |
individual terms: |
[Fe3+(aq)]1 |
|
[SCN-(aq)]1 |
|
[Fe(SCN)2+(aq)]1 |
Note: any number raised to the power of 1 is simply equal to that number, that is, 21 = 2, 10561 = 1056, etc
So, [Fe3+(aq)]1 = [Fe3+(aq)]
and [SCN-(aq)]1 = [SCN-(aq)]
and [Fe(SCN)2+(aq)]1 = [Fe(SCN)2+(aq)]
Step 3: Write the term for the numerator by multiplying together the terms for each product:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
1Fe3+(aq) |
+ |
1SCN-(aq) |
⇋ |
1Fe(SCN)2+(aq) |
individual terms: |
[Fe3+(aq)]1 |
|
[SCN-(aq)]1 |
|
[Fe(SCN)2+(aq)]1 |
numerator term: |
|
|
[Fe(SCN)2+(aq)] |
Step 4: Write the term for the denominator by multiplying together the terms for each reactant:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
1Fe3+(aq) |
+ |
1SCN-(aq) |
⇋ |
1Fe(SCN)2+(aq) |
individual terms: |
[Fe3+(aq)]1 |
|
[SCN-(aq)]1 |
|
[Fe(SCN)2+(aq)]1 |
numerator term: |
|
|
[Fe(SCN)2+(aq)] |
denominator term: |
[Fe3+(aq)][SCN-(aq)] |
|
|
Step 5: Write the mass-action expression, Q, by dividing the numerator by the denominator:
general reaction: |
reactants |
⇋ |
products |
reaction equation: |
1Fe3+(aq) |
+ |
1SCN-(aq) |
⇋ |
1Fe(SCN)2+(aq) |
individual terms: |
[Fe3+(aq)]1 |
+ |
[SCN-(aq)]1 |
⇋ |
[Fe(SCN)2+(aq)]1 |
numerator term: |
|
|
[Fe(SCN)2+(aq)] |
denominator term: |
[Fe3+(aq)][SCN-(aq)] |
|
|
mass-action expression, Q = |
numerator denominator |
= |
[Fe(SCN)2+(aq)] [Fe3+(aq)][SCN-(aq)] |