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Distance and Length Unit Conversions Chemistry Tutorial

Key Concepts

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Units of Length and Unit Conversions

You are probably already very familiar with some units for measuring distance.
We measure the distance between one town and another in kilometres.
We measure the height of a person in metres or centimetres.
My ruler is 30 centimetres long and each centimetre is divided into 10 millimetres.

But all the distances above are large enough to see. Chemists are interested in atoms and the distances between them which are much too small to be seen using only your eyes.
For example, some of the lengths, or distances, chemists are interested in are:

All of the lengths listed above are much, much, smaller than a metre.
Because the size of an atom and the distance between atoms in a molecule is of the order of 10-10 metres, a convenient unit of measurement is the Ångstrom (Å)(3) defined as 10-10 m

1 Å = 10-10 m

If an atom with has a radius of 1.54 Å we can convert this radius to metres as shown below:

1 Å = 10-10 m
multiply both sides of the equation by 1.54
1.54 × 1 Å = 1.54 × 10-10 m
1.54 Å = 1.54 × 10-10 m

But the Ångstrom, although very convenient, is not an SI unit and has been largely replaced by other units such as the nanometre (nm) and the picometre (pm):

If an atom has a radius of 1.54 × 10-10 m we can convert this to nanometres (nm) as shown below:

1 m = 109 nm
multiply both sides of the equation by 1.54 × 10-10
(1.54 × 10-10) × 1 m = (1.54 × 10-10) × 109 nm
1.54 × 10-10 m = 0.154 nm
in scientific notation this is 1.54 × 10-1 nm

We can also convert this radius of 1.54 × 10-10 m to picometres (pm) as shown below:

1 m = 1012 pm
multiply both sides of the equation by 1.54 × 10-10
(1.54 × 10-10) × 1 m = (1.54 × 10-10) × 1012 pm
1.54 × 10-10 m = 154 pm
in scientific notation this is 1.54 × 102 pm

Therefore, the radius of our atom can be represented in a number of different, but equivalent, ways:

We can also convert lengths in nanometres to picometres in a similar way.
An atom of fluorine has a radius of 71 pm.
We can convert this to a radius in nanometres as shown below:

1 pm = 10-12 m
multiply both sides of the equation by 71
71 × 1 pm = 71 × 10-12 m
radius of atom is 71 × 10-12 m
recall that 1 m = 109 nm
multiply 71 × 10-12 m by 109 nm/m
71 × 10-12 m = (71 × 10-12) × 109 nm
71 × 10-12 m = 71 × 10-3 nm
in scientific notation this is 7.1 × 10-2 nm

The table below lists the common prefixes attached to the metre (the SI unit of length):

  larger than 1 metre smaller than 1 metre
factors 1012 109 106 103 102 101 10-1 10-2 10-3 10-6 10-9 10-12 10-15 10-18
prefix tera giga mega kilo hecto deca deci centi milli micro nano pico femto atto
symbol T G M k h da d c m µ n p f a

This table tells us that:

We can use this determine how many of each unit are in a metre:

number of kilometres in a metre = 1 km ÷ 103 = 10-3 km/m

number of centimetres in a metre = 1 cm ÷ 10-2 = 102 cm/m

number of millimetres in a metre = 1 mm ÷ 10-3 = 103 mm/m

number of micrometres in a metre = 1 μm ÷ 10-6 = 106 μm/m

number of nanometres in a metre = 1 nm ÷ 10-9 = 109 nm/m

number of picometres in a metre = 1 pm ÷ 10-12 = 1012 pm/m

For chemistry students, the most important conversions are probably between metres (m), nanometres (nm) and picometres (pm):

1 nm = 10-9 m 109 nm = 1 m
1 pm = 10-12 m 1012 pm = 1 m
1 pm = 10-3 nm 103 pm = 1 nm

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Worked Examples of Length Conversions Using SI and Metric Units

Question 1: Convert a bond length of 1.4 × 10-10 m to nanometres.

Solution:

From the table above we see that 1 m = 109 nm

Multiply both sides of the equation by 1.4 × 10-10

1 m × (1.4 × 10-10) = 109 nm × (1.4 × 10-10)

1.4 × 10-10 m = 0.14 nm = 1.4 × 10-1 nm

Question 2: A beam of yellow light has a wavelength of 500 nm. Convert this to a wavelength in metres.

Solution:

From the table above we see that 1 nm = 10-9 m

Multiply both sides of the equation by 500

1 nm × 500 = 10-9 m × 500

500 nm = 5.00 × 10-7 m

Question 3: An atom of iodine has a radius of 220 pm. Convert this to a radius in metres.

Solution:

From the table above we see that 1 pm = 10-12 m

Multiply both sides of the equation by 220

1 pm × 220 = 10-12 m × 220

220 pm = 2.20 × 10-10 m

Question 4: A sodium ion has a radius of 1.02 × 10-10 m. Convert this to a radius in picometres.

Solution:

From the table above we see that 1 m = 1012 pm

Multiply both sides of the equation by 1.02 × 10-10

1 m × (1.02 × 10-10) = 1012 pm × (1.02 × 10-10)

1.02 × 10-10 m = 102 pm = 1.02 × 102 pm

Question 5: A chloride ion has a radius of 181 pm. Convert this to a radius in nanometres.

Solution:

From the table above we see that 1 pm = 10-12 m

Multiply both sides of the equation by 181

1 pm × 181 = 10-12 m × 181

181 pm = 1.81 × 10-10 m

From the table above, 1 m = 109 nm

Multiply both sides of the equation by 1.81 × 10-10

1 m × (1.81 × 10-10) = 109 nm × (1.81 × 10-10)

1.81 × 10-10 m = 0.181 nm = 1.81 × 10-1 nm

Question 6: A nanoparticle is known to have a diameter of 78 nm. Convert this to a diameter in picometres.

Solution:

From the table above we see that 1 nm = 10-9 m

Multiply both sides of the equation by 78

1 nm × 78 = 10-9 m × 78

78 nm = 7.8 × 10-8 m

From the table above we see that 1 m = 1012 pm

Multiply both sides of the equation by 7.8 × 10-8

1 m × (7.8 × 10-8) = 1012 pm × (7.8 × 10-8)

7.8 × 10-8 m = 78000 pm = 7.8 × 104 pm

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Footnotes:

(1) SI stands for Systéme International d'Unités

(2) In 1960 the General Conference of Weights and Measures recommended the use of the meter (metre) as the base unit of length.
Why are there two different spellings?
In English, "meter" refers to the act of measuring, while a "metre" is a unit of measurement.
Since both spellings are commonly applied to the unit of length we have included both here.

(3) The Ångstom is named after 19th century Swedish physicist A.J.Ångstrom