Half-Life of Radioisotopes Chemistry Tutorial
Key Concepts
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Defining the Half-life of a Radioisotope
The half-life of a radioisotope is the time it takes for half the original number of atoms of the isotope to undergo nuclear decay (radioactive decay).
Some radioisotopes have very long half-lives, some have very short half-lives.
The half-life of some radioisotopes is given in the table below:
Name |
Symbol |
Half-life (t½) |
fluorine-20 |
|
11 seconds |
magnesium-27 |
|
9.5 minutes |
sodium-24 |
|
15 hours |
iodine-131 |
|
8 days |
cobalt-60 |
|
5.3 years |
tritium (hydrogen-3) |
|
12.3 years |
strontium-90 |
|
28 years |
carbon-14 |
|
5,700 years |
radium-226 |
|
1,600 years |
plutonium-239 |
|
24,000 years |
uranium-238 |
|
4,500,000,000 years |
The earth is about 4.5 × 109 years old.
The half-life of uranium-238 is also about 4.5 × 109 years.
This means that if a rock contained 100 g of uranium-238 at the time the earth came into being, then at the present time the rock would contain only half that amount, ½ × 100 = 50 g, of uranium-238.
If you wait another 4.5 × 109 years and measure the mass of uranium-238 in that rock you will find there will be only ½ × 50 = 25 g left.
We could tabulate the mass of uranium-238 remaining after an interval of time measured in numbers of half-lives as shown below:
Time as a number of half-lives |
Time elapsed in years |
Mass of Uranium-238 (g) |
0 |
0 |
100.0 g |
1 |
4.50 × 109 |
50.00 g |
2 |
9.00 × 109 |
25.00 g |
3 |
1.35 × 1010 |
12.50 g |
4 |
1.80 × 1010 |
6.250 g |
5 |
2.25 × 1010 |
3.125 g |
And we could plot the mass of uranium-238 in the rock against time on a graph as shown below:
mass (g)
|
Mass of 238U in rock
time (× 1010 years)
|
We could then use this graph to find the mass of uranium-238 remaining in the sample of rock at any time.
For example, if we want to know how much uranium-238 is in the rock after 1 × 1010 years, we can read it straight of the graph as a mass of approximately 21.5 grams.
Similarly, we could determine how long we would have to wait in order for there to be only 75 grams of uranium-238 left in the rock.
Reading this off the graph, we see that the answer is about 0.18 × 1010 years.
Determining Half-life of a Radioisotope from Data Tables and Graphs
In an experiment, the mass of strontium-90 in a given sample of bone was measured every 7 years.
The results are shown in the table below:
time elapsed in years |
mass of strontium-90 in bone (mg) |
0 |
36.00 |
7 |
30.27 |
14 |
25.46 |
21 |
21.41 |
28 |
18.00 |
35 |
15.14 |
42 |
12.73 |
49 |
10.70 |
56 |
9.000 |
63 |
7.570 |
We can determine the half-life of strontium-90 by inspecting the mass of strontium-90 remaining in the bone.
Remember, half-life of a radioisotope is defined as the time it takes for half the isotope to undergo nuclear decay.
At time 0, the mass of strontium-90 in the bone is 36.00 mg.
After one half-life, only half this amount of strontium-90 will remain, that is, mass of strontium-90 will be ½ × 36.00 mg = 18.00 mg
From the table we see that it takes 28 years for the mass of strontium-90 in the bone to be 18.00 mg so the half-life of strontium-90 is 28 years (t½ = 28 years)
We can see that we can take any time interval of 28 years and find that the mass of strontium-90 in the bone will be halved:
For example, at time = 7 years the mass of strontium-90 is 30.27 mg, then after 1 half-life (7 + 28 = 35 years), the mass of strontium-90 is ½ × 30.27 mg = 15.14 mg
If the results of the experiment were presented in a graph we could use the graph to determine the half-life of strontium-90 in the same way:
mass (mg)
|
Mass of 90Sr in bone
time (years)
|
Choose a point on the graph, for example, at time 21 years the mass of strontium-90 is 21.41 mg
After one half-life, the mass of strontium-90 will be ½ × 21.41 mg = 10.70 mg
From the graph, read off the value of time when the mass is 10.70 mg
time = 49 years.
The half-life is the time it takes for 21.41 mg to be halved to 10.70 g, that is,
the half-life of strontrium-90 is 49 - 21 = 28 years.
Calculating the Amount of Radioisotope Remaining in a Sample
If you know:
- how much radioisotope was present in a sample at a given time, No
- half-life of that radioisotope, t½
- how much time has elapsed, t
then you calculate the mass of radioisotope remaining in the sample, Nt:
Nt = No × (0.5)t/t½
For example, iodine-131 has a half-life of 8 days.
If we start our experiment with a mass of 1.50 g of iodine-131, how much iodine-131 will be present in 14 days time?
No = 1.50 g
t½ = 8 days
t = 14 days
Nt = No × (0.5)t/t½
Nt = 1.50 × (0.5)14/8 = 0.446 g
Note the t ÷ t½ is actually the time that has elapsed in terms of the number of half-lives.
In the example above, t ÷ t½ = 14 ÷ 8 = 1.75 half-lives
So we could re-write our equation in terms of the number of half-lives that has elapsed:
Nt = No × (0.5)number of half-lives
For our 1.50 g sample of iodine-131, if we wait 5 half-lives (5 × 8 = 40 days), then the amount of iodine-131 remaining in the sample will be:
Nt = No × (0.5)number of half-lives
Nt = 1.50 × (0.5)5 = 0.0469 g
Calculating How Much Radioisotope has Decayed
If we know:
- how much radioisotope was present in the original sample, No
- how much radioisotope is present in the sample after time t, Nt
we can calculate how much of the radioisotope has undergone nuclear decay (Nd):
Nd = No - Nt
For example, the mass of iodine-131 remaining in a sample of iodine-131 after 40 days is 0.0469 g.
If the sample originally contained 1.50 g of iodine-131, what mass of iodine-131 has undergone nuclear decay?
No = 1.50 g
Nt = 0.0469 g
Nd = No - Nt = 1.50 - 0.0469 = 1.45 g
You could also express this amount as a percentage.
What percentage of the iodine-131 has undergone radioactive decay?
%Nd |
= |
Nd No |
× 100 |
|
= |
1.45 1.50 |
× 100 |
|
= |
96.7 % |
And you could use this to calculate the percentage of iodine-131 that still remains in the sample:
%Nt |
= |
100 - %Nd |
|
= |
100 - 96.7 |
|
= |
3.30 % |