go to the AUS-e-TUTE homepage

Period 4 Subshell Electronic Configuration Tutorial

Key Concepts

Aufbau Principle (Aufbau Rule)

"Aufbau" is a german word meaning construction or "building up". The Aufbau principle (or Aufbau rule), formulated in the 1920s by Neils Bohr and Wolfgang Pauli, is used to help us write the electronic configuration of an atom in terms of energy levels and subshells. It is important to remember that this is a hypothetical "building-up" of electrons around an atom's nucleus, it is a generalised tool that enables us to write the electronic configuration of an atom but it does not necessarily represent the experimentally determined energy values for the subshells of particular atoms.1

The Aufbau principle tells us to fill the lower energy subshells with electrons first, before filling subshells of higher energy with electrons.

For the first 20 elements we can represent the energy levels and subshells as shown below with the order of filling shown by red arrows:

4th energy level
(N shell)
____      
4s____(maximum of 2 electrons)
 
↑ 6th
3rd energy level
(M shell)
____     3p____(maximum of 6 electrons)
3s____(maximum of 2 electrons)
↑ 5th
↑ 4th
     
2nd energy level
(L shell)
____   2p____(maximum of 6 electrons)
2s____(maximum of 2 electrons)
↑ 3rd
↑ 2nd
     
1st energy level
(K shell)
 
____
   
1s____ (maximum of 2 electrons)
↑ 1st

energy
levels
(shells)
      sublevels
(subshells)
filling order

But when we come to the first of the transition metals, d subshell in period 4, we hit a snag.


So our energy level diagram looks more like the one shown below with the "order of filling" given by the red arrows:

4th energy level
(N shell)
____     4p____(maximum of 6 electrons)
3d____(maximum of 10 electrons)
4s____(maximum of 2 electrons)
↑ 8th
↑ 7th
↑ 6th
3rd energy level
(M shell)
____     3p____(maximum of 6 electrons)
3s____(maximum of 2 electrons)
↑ 5th
↑ 4th
     
2nd energy level
(L shell)
____   2p____(maximum of 6 electrons)
2s____(maximum of 2 electrons)
↑ 3rd
↑ 2nd
     
1st energy level
(K shell)
 
____
   
1s____ (maximum of 2 electrons)
↑ 1st

energy
levels
(shells)
      sublevels
(subshells)
filling order

The Aufbau principle is usually represented as a "filling diagram" as shown below:

We follow the direction of the arrows to place electrons 1 at a time into their subshells in order to "build up" the electronic configuration of an atom.
We could write this "filling order" out as a series of steps:
Step 1: add electrons to fill the 1s subshell (maximum of 2 electrons), when this is full, go to step 2.
Step 2: add electrons to fill the 2s subshell (maximum of 2 electrons), when this is full, go to step 3.
Step 3: add electrons to fill the 2p subshell (maximum of 6 electrons), when this is full, go to step 4.
Step 4: add electrons to fill the 3s subshell (maximum of 2 electrons), when this is full, go to step 5.
Step 5: add electrons to fill the 3p subshell (maximum of 6 electrons), when this is full, go to step 6.
Step 6: add electrons to the 4s subshell (maximum of 2 electrons), when this is full, go to step 7.
Step 7: add electrons to the 3d subshell (maximum of 10 electrons), when this is full, go to step 8.
Step 8: add electrons to the 4p subshell (maximum of 6 electrons), when this is full, go to step 9.
etc

You can use the Aufbau principle to correctly predict the electronic configuration of the atoms of most elements.
However, if we consider an atom of chromium, Z=24, the Aufbau principle predicts its electronic configuration to be:
1s22s22p63s23p64s23d4
which, when we collect subshells of the same energy level together, is written as:
1s22s22p63s23p63d44s2

Experimental evidence tells us that the electronic configuration of an atom of chromium is actually:
1s22s22p63s23p63d54s1

that is, the atom's ground state electronic configuration is more stable, of lower energy, if both the 4s and 3d subshells are half-filled.2

Similarly, when we come to copper, Z=29, the Aufbau principle predicts its electronic configuration to be:

1s22s22p63s23p64s23d9
which, when we collect subshells of the same energy level together, is written as:
1s22s22p63s23p63d94s2

Experimental evidence tells us that the electronic configuration of an atom of copper is actually:
1s22s22p63s23p63d104s1

that is, the atom's ground state electronic configuration is more stable, of lower energy, if the 3d subshell is filled leaving the 4s subshell half-filled.

Do you know this?

Join AUS-e-TUTE!

Play the game now!

s Block Electronic Configuration

There are 2 elements in the s block of period 4, potassium (K, Group 1) and calcium (Ca, Group 2).

  Group 1 Group 2 Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Group 11 Group 12 Group 13 Group 14 Group 15 Group 16 Group 17 Group 18
  s block d block p block
Period 4 Z=19
K
Z=20
Ca
Z=21
Sc
Z=22
Ti
Z=23
V
Z=24
Cr
Z=25
Mn
Z=26
Fe
Z=27
Co
Z=28
Ni
Z=29
Cu
Z=30
Zn
Z=31
Ga
Z=32
Ge
Z=33
As
Z=34
Se
Z=35
Br
Z=36
Kr

Just like we did for the atoms of elements in Periods 1, 2 and 3, we can draw a diagram representing the energy levels and subshells available to these s block elements of the fourth period:

4th energy level
(N shell)
____      
4s____(maximum of 2 electrons)
3rd energy level
(M shell)
____     3p____(maximum of 6 electrons)
3s____(maximum of 2 electrons)
     
2nd energy level
(L shell)
____   2p____(maximum of 6 electrons)
2s____(maximum of 2 electrons)
     
1st energy level
(K shell)
 
____
   
1s____ (maximum of 2 electrons)

energy
levels
(shells)
      sublevels
(subshells)

The order for filling the subshells with electrons is therefore:

1s < 2s < 2p < 3s < 3p < 4s

Atoms of both potassium and calcium have the same "core" electronic configuration, that of the preceding Noble Gas (Group 18 element) which is argon,

1s2 2s2 2p6 3s2 3p6

and electrons are being added to the s subshell of the fourth energy level, that is, electrons are being added to fill the 4s subshell which can house a maximum of 2 electrons:
1s2 2s2 2p6 3s2 3p6 4s
OR
[Ar] 4s

potassium (Z=19) has one electron positioned in the 4s subshell:


subshell electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s1
condensed electronic configuration: [Ar] 4s1

calcium (Z=20) has two electrons located in the 4s subshell:


subshell electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s2
condensed electronic configuration: [Ar] 4s2

With an atom of calcium, the 4s subshell is now full of electrons.

Do you understand this?

Join AUS-e-TUTE!

Take the test now!

d Block (transition metal) Electronic Configuration

There are 10 transition metal elements in the d block of this period:

  Group 1 Group 2 Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Group 11 Group 12 Group 13 Group 14 Group 15 Group 16 Group 17 Group 18
  s block
4th Energy Level
d block
3rd Energy Level
p block
4th Energy Level
Period 4 Z=19
K
Z=20
Ca
Z=21
Sc
Z=22
Ti
Z=23
V
Z=24
Cr
Z=25
Mn
Z=26
Fe
Z=27
Co
Z=28
Ni
Z=29
Cu
Z=30
Zn
Z=31
Ga
Z=32
Ge
Z=33
As
Z=34
Se
Z=35
Br
Z=36
Kr

Scandium is the first of the transition metal or d block elements.
The d subshell for atoms of period 4 elements belongs to the third energy level, that is, the 3d subshell.
We now need to include this 3d subshell in our generalised "filling diagram":

4th energy level
(N shell)
____     3d____(maximum of 10 electrons)
4s____(maximum of 2 electrons)
3rd energy level
(M shell)
____     3p____(maximum of 6 electrons)
3s____(maximum of 2 electrons)
     
2nd energy level
(L shell)
____   2p____(maximum of 6 electrons)
2s____(maximum of 2 electrons)
     
1st energy level
(K shell)
 
____
   
1s____ (maximum of 2 electrons)

energy
levels
(shells)
      sublevels
(subshells)

The order for filling the subshells with electrons is therefore:

1s < 2s < 2p < 3s < 3p < 4s < 3d

Note that when we write the electronic configuration of these atoms we keep all the subshells of the same energy level together3: 1s 2s 2p 3s 3p 3d 4s
We can follow this sequence to write the electronic configurations of the first few d block elements:
scandium (Z=21)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d1
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d1 4s2     or     [Ar] 3d14s2

titanium (Z=22)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d2
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d2 4s2     or     [Ar] 3d24s2

vanadium (Z=23)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d3
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d3 4s2     or     [Ar] 3d34s2


But what happens next?
If we follow the filling sequence for chromium (Z=24) we would end up with a filled 4s subshell (4s2) and nearly half-filled 3d subshell (3d4).
So what?
The most stable electronic configurations for an atom occur in one of two ways:
So the most stable electronic configuration for an atom of chromium is to have both its 4s and 3d subshells half-filled!
chromium (Z=24)
Using the filling sequence with half-filled 4s and 3d subshells: 1s2 2s2 2p6 3s2 3p6 4s1 3d5
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d5 4s1     or     [Ar] 3d54s1

With manganese (Z=25) we can pair up that lone 4s electron while keeping the stable half-filled 3d subshell:
manganese (Z=25)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d5
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d5 4s2     or     [Ar] 3d54s2

And we can continue to add more electrons to the 3d subshell for the next few atoms:
iron (Z=26)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d6
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d6 4s2     or     [Ar] 3d64s2

cobalt (Z=27)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d7
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d7 4s2     or     [Ar] 3d74s2

Nickel (Z=28)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d8
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d8 4s2     or     [Ar] 3d84s2


Until we arrive at copper (Z=29).
If we continue using the filling sequence we would end up with a filled 4s subshell (4s2), and a nearly completely full 3d subshell (3d9).
Now remember that the most stable electronic configurations for an atom occur in one of two ways:
So the most stable electronic configuration for an atom of copper is to have a completely filled 3d subshell and a half-filled 4s subshell:
copper (Z=29)
Using filling sequence with half-filled 4s and completely filled 3d subshell: 1s2 2s2 2p6 3s2 3p6 4s1 3d10
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s1     or     [Ar] 3d104s1

The last element in the d block of period 4 is zinc (Z=30) and it will have completely filled 4s and 3d subshells:
zinc (Z=30)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d10
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2     or     [Ar] 3d104s2

Do you understand this?

Join AUS-e-TUTE!

Take the test now!

p Block Electronic Configuration

There are 6 elements in the p block of the fourth period:

  Group 1 Group 2 Group 3 Group 4 Group 5 Group 6 Group 7 Group 8 Group 9 Group 10 Group 11 Group 12 Group 13 Group 14 Group 15 Group 16 Group 17 Group 18
  s block
4th Energy Level
d block
3rd Energy Level
p block
4th Energy Level
Period 4 Z=19
K
Z=20
Ca
Z=21
Sc
Z=22
Ti
Z=23
V
Z=24
Cr
Z=25
Mn
Z=26
Fe
Z=27
Co
Z=28
Ni
Z=29
Cu
Z=30
Zn
Z=31
Ga
Z=32
Ge
Z=33
As
Z=34
Se
Z=35
Br
Z=36
Kr

The 4p subshell is of higher energy than the 4s and 3d subshells, so the representation we use for filling these subshells looks familiar:

4th energy level
(N shell)
____     4p____(maximum of 6 electrons)
3d____(maximum of 10 electrons)
4s____(maximum of 2 electrons)
3rd energy level
(M shell)
____     3p____(maximum of 6 electrons)
3s____(maximum of 2 electrons)
     
2nd energy level
(L shell)
____   2p____(maximum of 6 electrons)
2s____(maximum of 2 electrons)
     
1st energy level
(K shell)
 
____
   
1s____ (maximum of 2 electrons)

energy
levels
(shells)
      sublevels
(subshells)

The order for filling the subshells with electrons is therefore:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p

Gallium (Z=31) has the 4s and 3d subshells full and just 1 electron in a 4p subshell:
gallium (Z=31)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p1     or     [Ar] 3d104s24p1

1 electron is added to the 4p subshell for each subsequent atom in period 4:
germanium (Z=32)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p2     or     [Ar] 3d104s24p2

arsenic (Z=33)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p3
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3     or     [Ar] 3d104s24p3

selenium (Z=34)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4     or     [Ar] 3d104s24p4

bromine (Z=35)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p5
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5     or     [Ar] 3d104s24p5

krypton (Z=36)
Using the filling sequence: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
Writing the electronic configuration: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6     or     [Ar] 3d104s24p6


The Group 18 (Noble Gas) element krypton is the last element in period 4 of the periodic table, and has all its available subshells completely filled with electrons.

Do you understand this?

Join AUS-e-TUTE!

Take the test now!

Summary

The electronic configurations of the first 36 elements is given below in subshell notation and as a condensed electronic configuration:

Period name
(symbol)
subshell
electron configuration
condensed
electron configuration
Period 1

(tutorial)

hydrogen
(H)
1s1  
helium
(He)
1s2  
Period 2

(tutorial)

lithium
(Li)
1s2 2s1 [He] 2s1
beryllium
(Be)
1s2 2s2 [He] 2s2
boron
(B)
1s2 2s2 2p1 [He] 2s2 2p1
carbon
(C)
1s2 2s2 2p2 [He] 2s2 2p2
nitrogen
(N)
1s2 2s2 2p3 [He] 2s2 2p3
oxygen
(O)
1s2 2s2 2p4 [He] 2s2 2p4
fluorine
(F)
1s2 2s2 2p5 [He] 2s2 2p5
neon
(Ne)
1s2 2s2 2p6 [He] 2s2 2p6
Period 3

(tutorial)

sodium
(Na)
1s2 2s2 2p6 3s1 [Ne] 3s1
magnesium
(Mg)
1s2 2s2 2p6 3s2 [Ne] 3s2
aluminium
(Al)
1s2 2s2 2p6 3s2 3p1 [Ne] 3s2 3p1
silicon
(Si)
1s2 2s2 2p6 3s2 3p2 [Ne] 3s2 3p2
phosphorus
(P)
1s2 2s2 2p6 3s2 3p3 [Ne] 3s2 3p3
sulfur
(S)
1s2 2s2 2p6 3s2 3p4 [Ne] 3s2 3p4
chlorine
(Cl)
1s2 2s2 2p6 3s2 3p5 [Ne] 3s2 3p5
argon
(Ar)
1s2 2s2 2p6 3s2 3p6 [Ne] 3s2 3p6
Period 4 potassium
(K)
1s2 2s2 2p6 3s2 3p6 4s1 [Ar] 4s1
calcium
(Ca)
1s2 2s2 2p6 3s2 3p6 4s2 [Ar] 4s2
scandium
(Sc)
1s2 2s2 2p6 3s2 3p6 3d1 4s2 [Ar] 3d1 4s2
titanium
(Ti)
1s2 2s2 2p6 3s2 3p6 3d2 4s2 [Ar] 3d2 4s2
vanadium
(V)
1s2 2s2 2p6 3s2 3p6 3d3 4s2 [Ar] 3d3 4s2
chromium
(Cr)
1s2 2s2 2p6 3s2 3p6 3d5 4s1 [Ar] 3d5 4s1
manganese
(Mn)
1s2 2s2 2p6 3s2 3p6 3d5 4s2 [Ar] 3d5 4s2
iron
(Fe)
1s2 2s2 2p6 3s2 3p6 3d6 4s2 [Ar] 3d6 4s2
cobalt
(Co)
1s2 2s2 2p6 3s2 3p6 3d7 4s2 [Ar] 3d7 4s2
nickel
(Ni)
1s2 2s2 2p6 3s2 3p6 3d8 4s2 [Ar] 3d8 4s2
copper
(Cu)
1s2 2s2 2p6 3s2 3p6 3d10 4s1 [Ar] 3d10 4s1
zinc
(Zn)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 [Ar] 3d10 4s2
gallium
(Ga)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p1 [Ar] 3d10 4s2 4p1
germanium
(Ge)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p2 [Ar] 3d10 4s2 4p2
arsenic
(As)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 [Ar] 3d10 4s2 4p3
selenium
(Se)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4 [Ar] 3d10 4s2 4p4
bromine
(Br)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5 [Ar] 3d10 4s2 4p5
krypton
(Kr)
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 [Ar] 3d10 4s2 4p6

Can you apply this?

Join AUS-e-TUTE!

Take the exam now!

1Experimental evidence reveals that for the transition metals, the 3d subshells are actually of lower energy than the 4s subshell. Hence, period 4 transition metals ionise by losing the electrons in the highest energy levels first, that is, from the 4s subshell. These 4s electrons are shielded by the lower energy 3d electrons, making them easier to remove. For the transition metals it is energetically favourable for electrons to occupy both the 4s and 3d subshells rather than just filling the lower energy 3d subshell first.
The graphical representations of "filling order" are therefore only a general guide to writing an electronic configuration, in reality the actual energy values for subshells are different for each atom based on considerations of electrostaic-type attractions and repulsions between the species making up each atom, so that these general representations should be "tweaked" to represent the energy values for each particular atom.

2This is arrived at by the application of "Hund's Rule": if multiple orbitals of the same energy level are available, electrons fill unoccupied orbitals singly first before pairing up with an electron in the same orbital.

3Notice that writing the electronic configuration of the transition metals in this way, ie, 3d before 4s, actually gives a better representation of the relative energies of the 3d and 4s electrons, that is, 4s electrons are of higher energy than 3d electrons and hence are written last in the electronic conifguration.