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Electronegativity and Bond Polarity Chemistry Tutorial

Key Concepts

Electronegativity


1
H
2.1
The number on top of the element's symbol is its atomic number, Z (the number of protons in the nucleus).
In the middle of the box there is a letter (or letters), the symbol for the element.
The number underneath the symbol is the electronegativity of the element using Pauling's method.
Period Group
1
Group
2
Transition Metals Group
13
Group
14
Group
15
Group
16
Group
17
Group
18
1   2
He
-
2 3
Li
1.0
4
Be
1.5
  5
B
2.0
6
C
2.5
7
N
3.0
8
O
3.5
9
F
4.0
10
Ne
-
3 11
Na
0.9
12
Mg
1.2
  13
Al
1.5
14
Si
1.8
15
P
2.1
16
S
2.5
17
Cl
3.0
18
Ar
-
4 19
K
0.8
20
Ca
1.0
21
Sc
1.3
22
Ti
1.5
23
V
1.6
24
Cr
1.6
25
Mn
1.5
26
Fe
1.8
27
Co
1.9
28
Ni
1.9
29
Cu
1.9
30
Zn
1.6
31
Ga
1.6
32
Ge
1.8
33
As
2.0
34
Se
2.4
35
Br
2.8
36
Kr
-
5 37
Rb
0.8
38
Sr
1.0
39
Y
1.2
40
Zr
1.4
41
Nb
1.6
42
Mo
1.8
43
Tc
1.9
44
Ru
2.2
45
Rh
2.2
46
Pd
2.2
47
Ag
1.9
48
Cd
1.7
49
In
1.7
50
Sn
1.8
51
Sb
1.9
52
Te
2.1
53
I
2.5
54
Xe
-
6 55
Cs
0.7
56
Ba
0.9
57
La
1.1
72
Hf
1.3
73
Ta
1.5
74
W
1.7
75
Re
1.9
76
Os
2.2
77
Ir
2.2
78
Pt
2.2
79
Au
2.4
80
Hg
1.9
81
Tl
1.8
82
Pb
1.9
83
Bi
1.9
84
Po
2.0
85
At
2.2
86
Rn
-
7 87
Fr
0.7
88
Ra
0.9
89
Ac
1.1
104
Rf
-
105
Ha
-
 

Bond Polarity

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Example: Non-polar covalent bonds

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Example: Polar covalent bonds

Consider the O-H bond.

Electronegativity of O is 3.5

Electronegativity of H is 2.1

Difference in electronegativity: Oelectronegativity - Helectronegativity = 3.5 - 2.1 = 1.4

1.4 is less than 1.7, so the resulting bond is polar covalent.

Oxygen is the more electronegative so it will have a greater share of the bonding electrons and therefore a partial negative charge, Oδ-
Hydrogen is less electronegative so it will have a lesser share of the bonding electrons and therefore a partial positive charge, Hδ+
Since the bond has two 'poles' or 'ends' it is sometimes referred to as a dipole.
The polar covalent bond can be represented as:
δ-O-Hδ+ OR O-H

Where the arrow head points towards the most electronegative atom.

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Example: Ionic bonds

Consider the Na - F bond.

Electronegativity of Na is 0.9

Electronegativity of F is 4.0.

Difference in electronegativity: Felectronegativity - Naelectronegativity = 4.0 - 0.9 = 3.1

3.1 is greater than 1.7, so the resulting bond is ionic.


F has such a strong attraction for electrons that it pulls the electron off the Na resulting in a negative charge for fluorine, F-, and a positive charge for sodium, Na+
The bond between Na+ and F- is NOT covalent since the bonding electrons are not shared between the 'atoms'. Rather the bond is ionic since there has been a transfer of electrons from the least electronegative atom to the more electronegative atom resulting in two ions of opposite charge.
The best representation of this ionic compound is:

Na+F-

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