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Periodic Table: Trends in Atomic Radius and Ionic Radius Chemistry Tutorial

Key Concepts

In general, for the main group elements of the periodic table:

    atomic radius decreases across a period from left to right
    largest smallest
atomic radius
increases down
a group from
top to bottom
smallest Li Be   B C N O F Ne
Na Mg   Al Si P S Cl Ar
K Ca   Ga Ge As Se Br Kr
Rb Sr   In Sn Sb Te I Xe
largest Cs Ba   Tl Pb Bi Po At Rn

Note trends for ionic radii:

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Trends in Atomic Radius in Groups of the Periodic Table

As you go down a Group in the Periodic Table from top to bottom, the number of energy levels or electron shells increases so the atomic radius of the elements increases.

Compare the number of occupied energy levels (electron shells) and the radius of the atom of elements in Group 1 and in Group 17 as given in each section below:

(A) Trends in the Atomic Radius of Group 1 (IA, Alkali Metals) Elements

Use the data in the table below for Group 1 elements to look for a pattern (or trend) in

Element Atomic
Number
(Z)
Symbol Simple
Electron
Configuration
No. Energy Levels
(electron shells)
Atomic
Radius
(pm)3
Trend
lithium 3 Li 2,1 2 134 smallest
|
sodium 11 Na 2,8,1 3 154
potassium 19 K 2,8,8,1 4 196
rubidium 37 Rb 2,8,18,8,1 5 211
cesium 55 Cs 2,8,18,18,8,1 6 225
largest

As you go down Group 1:

Atomic radius increases as you go down the Group 1 elements from top to bottom as an additional energy level (electron shell) is being added to each successive element.

(B) Trends in the Atomic Radius of Group 17 (VIIA, Halogens) Elements

Use the data in the table below for Group 17 elements to look for a pattern (or trend) in

Element Atomic
Number
(Z)
Symbol Simple Electron Configuration No. Energy Levels
(electron shells)
Atomic Radius (pm) Trend
fluorine 9 F 2,7 2 71 (smallest)
chlorine 17 Cl 2,8,7 3 99
bromine 35 Br 2,8,18,7 4 114
iodine 53 I 2,8,18,18,7 5 133
(largest)

As you go down Group 17:

Atomic radius increases as you go down the Group 17 elements from top to bottom as an additional energy level (electron shell) is being added to each successive element.

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Trends in Atomic Radius in Periods of the Periodic Table

In general, the atomic radius of elements decreases as you go across a Period from left to right.

As we go across a Period from left to right, electrons are being added to the same energy level, the valence shell.
The increased nuclear charge, due to the positively charged protons, attracts all the negatively charged electrons more strongly so all the electrons are drawn in closer to the nucleus, in other words, the radius of each successive atom gets smaller across a period of the Periodic Table.

In the sections below we will consider the trends in the atomic radius of period 2 elements, and, of period 3 elements.

(A) Trends in the Atomic Radius of Elements in Period 2

Use the data given in the table below to find patterns (trends) in

Element Li Be B C N O F Ne
Simple Electron Configuration 2,1 2,2 2,3 2,4 2,5 2,6 2,7 2,8
Energy Level being filled
(Valence Shell)
second
(L)
second
(L)
second
(L)
second
(L)
second
(L)
second
(L)
second
(L)
second
(L)
Nuclear Charge
(charge on all protons)
3+ 4+ 5+ 6+ 7+ 8+ 9+ 10+
Atomic Radius (pm) 134 90 82 77 75 73 71 69
General Trend (largest) (smallest)

Can you see these patterns (trends):

Atomic radius generally decreases across Period 2 from left to right as the nuclear charge increases.

(B) Trends in the Atomic Radius of Elements in Period 3

Use the data given in the table below to find patterns (trends) in

Element Na Mg Al Si P S Cl Ar
Simple Electron Configuration 2,8,1 2,8,2 2,8,3 2,8,4 2,8,5 2,8,6 2,8,7 2,8,8
Energy Level being filled
(Valence Shell)
third
(M)
third
(M)
third
(M)
third
(M)
third
(M)
third
(M)
third
(M)
third
(M)
Nuclear Charge
(charge on all protons)
11+ 12+ 13+ 14+ 15+ 16+ 17+ 18+
Atomic Radius (pm) 154 130 118 111 106 102 99 97
General Trend (largest) (smallest)

Can you see these patterns (trends):

Atomic radius generally decreases across Period 3 from left to right as the nuclear charge increases.

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Ionic Radius

Let's compare the radius of some elements' atoms with their respective ions.
Group 1 elements form cations with a charge of +1
Group 17 elements form anions with a charge of -1

(A) Comparison of Atomic and Ionic Radius of Group 1 (IA, alkali metals) Elements

Atoms of group 1 elements (M) lose 1 electron (e-) from their valence shell of electrons to form a cation with a charge of +1 (M+)
We can wrote a chemical equation to represent this for any group 1 element (M) as shown below

atom cation + electron
M M+ + e-

We can write a specific equation to represent the formation of each cation of each group 1 element as shown below:

atom cation + electron
Li Li+ + e-
Na Na+ + e-
K K+ + e-
Rb Rb+ + e-
Cs Cs+ + e-

Consider the data in the table below. Can you see any patterns (or trends) in the data?

Compare each atom and its respective cation with regards to:

Element Symbol of Atom Atoms' Simple
Electron
Configuration
Atomic
Radius
(pm)
Symbol of Ion Ion's Simple
Electron
Configuration
Ionic
Radius4
(pm)
Trend
lithium Li 2,1 134 Li+ 2 74 smallest
sodium Na 2,8,1 154 Na+ 2,8 102
potassium K 2,8,8,1 196 K+ 2,8,8 138
rubidium Rb 2,8,18,8,1 211 Rb+ 2,8,18,8 149
cesium Cs 2,8,18,18,8,1 225 Cs+ 2,8,18,18,8 170
largest

Did you notice that:

As you go down the group from top to bottom, the ionic radius of each cation increases, just as it does for the radius of each atom because an energy level (electron shell) is being added to each successive atom (or ion).

However, if an electron is removed from a Group 1 atom it is removed from the highest energy level (valence shell), so this effectively reduces the number of occupied energy levels (or electron shells).
The same nuclear positive charge is now acting on fewer negatively charged electrons so these electrons are drawn in closer towards to the nucleus and the radius of the cation will be less than the radius of the atom.

(B) Comparison of Atomic and Ionic Radius of Group 17 (VIIA, halogen) Elements

1 electron (e-) can be added to the valence shell of the atoms of group 17 elements to form an anion with a charge of -1 (X-)
We can write a chemical equation to represent this for any group 17 element (X) as shown below

atom + electron anion
X + e- X-

We can write a specific equation to represent the formation of each anion of each group 17 element as shown below:

atom + electron anion
F + e- F-
Cl + e- Cl-
Br + e- Br-
I + e- I-

Consider the data in the table below. Can you see any patterns (or trends) in the data?

Compare each atom and its respective anion with regards to:

Element Symbol of Atom Atom's Simple Electron Configuration Atomic Radius (pm) Symbol of Ion Ion's Simple Electron Configuration Ionic Radius (pm) Trend
fluorine F 2,7 71 F- 2,8 131 (smallest)
chlorine Cl 2,8,7 99 Cl- 2,8,8 181
bromine Br 2,8,18,7 114 Br- 2,8,18,8 196
iodine I 2,8,18,18,7 133 I- 2,8,18,18,8 220
(largest)

Did you notice that:

Ionic radius increases as you go down the Group 17 elements from top to bottom as an additional energy level (electron shell) is being added to each successive element, just as it is for the neutral atom.

But what causes the radius to expand when an electron is added to the valence shell of the original atom?

The charge on the nucleus of the atom caused by the number of positively charged protons in the nucleus does not change when an electron is added to an electron shell.
But the number of negatively charged electrons in that electron shell does change!
And it means that there is a greater repulsion between all the electrons.
The effect of this repulsion between electrons is to increase the radius of the anion compared to the neutral atom.

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Problem Solving using StoPGoPS method

Question:

A student was given 3 specimen jars labelled X, Y and Z.
The jars contain samples of lead, silicon, and tin, but not necessarily in that order.
The student also received the results of an analysis to determine the atomic radius of the sample in each jar.
The results of the analysis is shown in the table below:

Sample atomic radius (pm)
X 180
Y 110
Z 145

Determine the name of the element in specimen jar Y.

STOP STOP! State the Question.
  What is the question asking you to do?
Name element Y
PAUSE PAUSE to Prepare a Game Plan
  (1) What information (data) have you been given in the question?

(a) Name of the three elements: lead, tin, silicon

(b) Atomic radius of the three elements:

radius (X) = 180 pm
radius (Y) = 110 pm
radius (Z) = 145 pm

(2) What is the relationship between what you know and what you need to find out?

(a) atomic radius increases down a group of the periodic table from top to bottom

(b) atomic radius decreases across a period of the periodic table from left to right.

GO GO with the Game Plan
 

(i) lead, tin and silicon below to the same group of the periodic table (group 14).

position Group 14 elements
top silicon
tin
bottom lead

(ii) atomic radius increases down a group from top to bottom, so write the names of the elements in order of increasing atomic radius:

position Group 14 elements Trend in atomic radius
top silicon smallest
tin
bottom lead largest

(iii) Place the values for atomic radii given in the question into the table (lowest to highest value):

position Group 14 elements Trend in atomic radius Atomic radius (pm)
top silicon smallest 110
tin 145
bottom lead largest 180

(iv) Correctly position X, Y, and Z in the table next to their respective atomic radii:

position Group 14 elements Trend in atomic radius Atomic radius (pm) Label
top silicon smallest 110 Y
tin 145 Z
bottom lead largest 180 X

Element Y is silicon.

PAUSE PAUSE to Ponder Plausibility
  Is your answer plausible?

Start with elements X, Y, and Z and place them in order of increasing atomic radius:

increasing atomic radius: 110 < 145 < 180
element: Y < Z < X

Then decide whether the elements lead, tin and silicon belong to the same group or period of the periodic table.
They all belong to the same group (group 14), so atomic radius increases as you go down the group.
The element at the top of the group is silicon so it will have the smallest radius, followed by tin, and lead at the bottom of the group will have the largest radius.
silicon radius < tin radius < lead radius
Therefore:

increasing atomic radius: 110 < 145 < 180
element: Y < Z < X
element: silicon < tin < lead

Element Y is silicon.
Since this answer is the same as the one we arrived at above, we are reasonably confident that our answer is plausible.

STOP STOP! State the Solution
  Element Y is silicon.

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Footnotes

1. The values for atomic radii provided here are approximations derived from interatomic-distance measurements.
There are a number of different ways of approaching the measurement of atomic and ionic radii. We are not going to discuss any of them, we are just going to use some nicely behaved approximations to illustrate some general trends.

2. We will be excluding transition metals, lanthanoids (lanthanides) and actinoids (actinides) from the disucssion

3. Common units for the reporting of atomic radii are the picometre (as used here), the nanometre, and the angstrom.
1 pm = 1 picometre = 10-12 metre
1 Å = 1 angstrom = 10-10 metre
1 nm = 1 nanometre = 10-9 metre
Conversion example for the atomic radius of lithium,
134 pm = 134 × 10-12 m = 0.134 × 10-9 m = 0.134 nm
134 pm = 134 × 10-12 m = 1.34 × 10-10 m = 1.34 Å

4. Ionic radius based on a coordination number of 6