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Identifying Structural Isomers of Haloalkanes (alkyl halides)
Structural isomers of halogenated methane, halomethane compounds, are not possible.
Structural isomers of halogenated alkanes only become possible where there are 2 or more carbon atoms present.
Consider ethane. It has the molecular formula C2H6 and the structural formula shown below:
If we replaced just 1 of the hydrogen atoms in ethane with a halogen atom, for example chlorine (Cl), we could produce the following 6 molecules with the molecular formula C2H5Cl:
structure a | structure b | structure c | structure d | structure e | structure f |
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Are these structures really different?
No. In each of these structures 3 H atoms are bonded to one of the C atoms and 2 H atoms and 1 Cl atom are bonded to the other carbon atom.
Since the structural formulae we have drawn above are really all the same we can say that structural isomers of C2H5Cl do not exist.
Consider what would happen if we replaced 2 of the hydrogen atoms in ethane with chlorine atoms.
1,1-dichloroethane, C2H4Cl2 |
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All these structures for 1,1-dichloroethane above are the same.
3 H atoms are bonded to one C atom, and, 1 H atom and 2 Cl atoms are bonded to the other C atom.
1,2-dichloroethane, C2H4Cl2 |
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All these structures for 1,2-dichloroethane are the same.
Each carbon atom is bonded to 2 H atoms and 1 Cl atom.
Both 1,1-dichlorethane and 1,2-dichlorethane have the same molecular formula, C2H4Cl2.
That is, one molecule of 1,1-dichloroethane contains 2 C atoms, 4 H atoms and 2 Cl atoms and one molecule of 1,2-dichloroethane also contains 2 C atoms, 4 H atoms and 2 Cl atoms.
However the structural formula of 1,1-dichloroethane is different to the structural formula of 1,2-dichloroethane.
In 1,1-dichloroethane both Cl atoms are attached to the same C atom, but in 1,2-dichloroethane the Cl atoms are attached to different C atoms.
1,1-dichloroethane and 1,2-dichloroethane are said to be structural isomers, or constitutional isomers.
These are molecules that have the same molecular formula but a different structural formula (or different constitutional formula).
It is possible to have structural isomers of haloalkanes (alkyl halides) when only 1 halogen atom is present, but you need 3 or more carbon atoms in the carbon chain (or carbon backbone or carbon skeleton).
Consider molecules with the molecular formula C4H9Cl
First we could just draw the structure for the straight-chain butane molecule and substitute a Cl atom for one of the H atoms in the structure to produce 1-chlorobutane and 2-chlorobutane:
| Cl | | | H | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
1-chlorobutane
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| H | | | Cl | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
2-chlorobutane
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Second, we could draw a 3 member carbon chain with a methyl side chain and then substitute a Cl atom for one of the H atoms, producing 1-chloro-2-methylpropane and 2-chloro-2-methylpropane:
| Cl | | | CH3 | | | H | | |
H- | C | - | C | - | C | -H |
| | H | | | H | | | H | |
1-chloro-2-methylpropane
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| H | | | CH3 | | | H | | |
H- | C | - | C | - | C | -H |
| | H | | | Cl | | | H | |
2-chloro-2-methylpropane
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There are four structural isomers with the molecular formula C4H9Cl.
These structural isomers are 1-chlorobutane, 2-chlorobutane, 1-chloro-2-methylpropane and 2-chloro-2-methylpropane.
Molecules are structural isomers only if they have:
- the same molecular formula
- different structural formula
Worked Examples of Deciding Whether Haloalkane Molecules are Structural Isomers
Example 1. Are the two haloalkane molecules shown below structural isomers?
| Cl | | | H | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
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| H | | | Br | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
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Step 1: write the molecular formula of each molecule:
| Cl | | | H | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
C4H9Cl |
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| H | | | Br | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
C4H9Br |
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The molecular formulae of the molecules are NOT the same.
C4H9Cl is NOT the same as C4H9Br
The two molecules are NOT structural isomers.
Example 2. Are the two haloalkane molecules shown below structural isomers?
| Cl | | | H | | | H | | | F | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
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| H | | | F | | | Cl | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
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Step 1: write the molecular formula of each molecule:
| Cl | | | H | | | H | | | F | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
C4H8ClF |
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| H | | | F | | | Cl | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
C4H8ClF |
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Both molecules have the same molecular formula.
We need to decide now if they have different structures.
Step 2: compare the structure of each molecule:
C4H8ClF |
| Cl | | | H | | | H | | | F | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
First C : 2 H, 1 Cl
Second C : 2 H
Third C : 2 H
Fourth C : 2 H, 1 F |
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C4H8ClF |
| H | | | F | | | Cl | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | H | |
First C : 3 H
Second C : 1 H, 1 F
Third C : 1 H, 1 Cl
Fourth C : 3 H |
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The arrangement of atoms in each molecule is different, that is, the structural formulae are different.
These two molecules ARE structural isomers.
Example 3. Are the two haloalkane molecules shown below structural isomers?
| Cl | | | H | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | F | | | H | | | H | | | H | |
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| H | | | H | | | H | | | Cl | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | F | |
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Step 1: write the molecular formula of each molecule:
| Cl | | | H | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | F | | | H | | | H | | | H | |
C4H8ClF |
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| H | | | H | | | H | | | Cl | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | F | |
C4H8ClF |
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Both molecules have the same molecular formula.
Now we need to compare the structural formula of each molecule.
Step 2: compare the structure of each molecule:
C4H8ClF |
| Cl | | | H | | | H | | | H | | |
H- | C | - | C | - | C | - | C | -H |
| | F | | | H | | | H | | | H | |
First C : 1 H, 1 Cl, 1 F
Second C : 2 H
Third C : 2 H
Fourth C : 3 H |
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C4H8ClF |
| H | | | H | | | H | | | Cl | | |
H- | C | - | C | - | C | - | C | -H |
| | H | | | H | | | H | | | F | |
First C : 3 H
Second C : 2 H
Third C : 2 H
Fourth C : 1 H, 1 Cl, 1 F |
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In both molecules the two central carbon atoms are bonded to 2 H atoms, one of the terminal (end) carbon atoms is bonded to 3 H atoms, and the other terminal (end) carbon atom is bonded to one atom of H, one atom of Cl and one atom of F.
These two molecules are NOT structural isomers, they have the same arrangement of atoms so they have the same structural formula.
(You could rotate the first molecule 180° in space to make the second molecule)