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Worked Example of Complete Combustion of an Alcohol
In this example we will be writing a balanced chemical equation to represent the complete combustion of ethanol.
Ethanol, C2H5OH(l) or CH3-CH2OH(l), widely used as a fuel, combusts in excess oxygen to produce carbon dioxide gas and water vapour.
Write a balanced chemical equation to represent the complete combustion of ethanol.
- Write the word equation for the complete combustion of ethanol.
Complete combustion of alcohols produces carbon dioxide gas and water vapour.
general equation: |
reactants |
→ |
products |
general word equation: |
alcohol |
+ |
oxygen gas |
→ |
carbon dioxide gas |
+ |
water vapour |
word equation for this reaction: |
ethanol |
+ |
oxygen gas |
→ |
carbon dioxide gas |
+ |
water vapour |
- Write the formula for each reactant and product in the word equation:
Reactants |
→ |
Products |
ethanol : oxygen gas : |
CH3-CH2OH(l) or C2H5OH(l) O2(g) |
|
carbon dioxide gas : water vapour : |
CO2(g) H2O(g) |
- Write the unbalanced chemical equation by substituting the formula for the name of each reactant and product in the word equation:
word equation : |
ethanol |
+ |
oxygen gas |
→ |
carbon dioxide gas |
+ |
water vapour |
unbalanced chemical equation : |
C2H5OH(l) |
+ |
O2(g) |
→ |
CO2(g) |
+ |
H2O(g) |
- Balance the chemical equation:
unbalanced chemical equation : |
C2H5OH(l) |
+ |
O2(g) |
→ |
CO2(g) |
+ |
H2O(g) |
|
No. C atoms : |
2 |
|
|
≠ |
1 |
|
|
C atoms NOT balanced |
Need to multiply the number of carbon dioxide molecules by 2 to balance the carbon atoms. |
|
C2H5OH(l) |
+ |
O2(g) |
→ |
2CO2(g) |
+ |
H2O(g) |
|
No. C atoms : |
2 |
|
|
= |
2 |
|
|
C atoms balanced |
Are hydrogen atoms balanced? |
No. H atoms : |
5+1 = 6 |
|
|
≠ |
|
|
2 |
H atoms NOT balanced |
Need to multiply the number of water molecules by 3 to balance the hydrogen atoms. |
|
C2H5OH(l) |
+ |
O2(g) |
→ |
2CO2(g) |
+ |
3H2O(g) |
|
No. H atoms : |
5+1 = 6 |
|
|
= |
|
|
3x2 = 6 |
H atoms balanced |
Are oxygen atoms balanced? |
|
C2H5OH(l) |
+ |
O2(g) |
→ |
2CO2(g) |
+ |
3H2O(g) |
|
No. O atoms : |
1 |
+ |
2 =3 |
≠ |
2x2 |
+ |
3x1 = 7 |
O atoms NOT balanced |
Need to multiply the number of oxygen molecules (O2) by 3 to balance the oxygen atoms. |
|
C2H5OH(l) |
+ |
3O2(g) |
→ |
2CO2(g) |
+ |
3H2O(g) |
|
No. O atoms : |
1 |
+ |
3x2 =7 |
= |
2x2 |
+ |
3x1 = 7 |
O atoms balanced |
- The balanced chemical equation for the complete combustion of ethanol is:
C2H5OH(l) + 3O2(g) → 2CO2(g) + 3H2O(g)
Worked Example of Incomplete Combustion of an Alcohol
In a particular experiment, excess ethanol was combusted in limited oxygen to produce soot (solid carbon), carbon monoxide gas and water vapour.
Write a balanced chemical equation to represent the incomplete combustion of ethanol in this experiment.
- Write the word equation for the incomplete combustion of methane:
general equation: |
reactants |
→ |
products |
general word equation: |
alcohol |
+ |
oxygen gas |
→ |
solid carbon |
+ |
carbon monoxide |
+ |
water vapour |
word equation for this reaction: |
ethanol |
+ |
oxygen gas |
→ |
solid carbon |
+ |
carbon monoxide |
+ |
water vapour |
- Write the formula for each reactant and product in the word equation:
Reactants |
|
Products |
ethanol : oxygen gas : |
C2H5OH(l) O2(g) |
|
solid carbon : carbon monoxide gas: water vapour : |
C(s) CO(g) H2O(g) |
- Write the unbalanced chemical equation by substituting the formula for the name of each reactant and product in the word equation:
word equation: |
ethanol |
+ |
oxygen gas |
→ |
solid carbon |
+ |
carbon monoxide |
+ |
water vapour |
unbalanced chemical equation: |
C2H5OH(l) |
+ |
O2(g) |
→ |
C(s) |
+ |
CO(g) |
+ |
H2O(g) |
- Balance the chemical equation:
unbalanced chemical equation : |
C2H5OH(l) |
+ |
O2(g) |
→ |
C(s) |
+ |
CO(g) |
+ |
H2O(g) |
|
No. C atoms : |
2 |
|
|
= |
1 |
+ |
1 =2 |
|
|
C atoms balanced |
Check to see if hydrogen atoms are balanced. |
|
C2H5OH(l) |
+ |
O2(g) |
→ |
C(s) |
+ |
CO(g) |
+ |
H2O(g) |
|
No. H atoms : |
5+1 =6 |
|
|
≠ |
|
|
|
|
2 |
H atoms NOT balanced |
Need to multiply the number of water molecules by 3 to balance the hydrogen atoms. |
|
C2H5OH(l) |
+ |
O2(g) |
→ |
C(s) |
+ |
CO(g) |
+ |
3H2O(g) |
|
No. H atoms : |
5+1 =6 |
|
|
= |
|
|
|
|
3x2 =6 |
H atoms balanced |
Check to see if oxygen atoms are balanced. |
|
C2H5OH(l) |
+ |
O2(g) |
→ |
C(s) |
+ |
CO(g) |
+ |
3H2O(g) |
|
No. O atoms : |
1 |
+ |
2 = 3 |
≠ |
|
|
1 |
+ |
3x1 =4 |
O atoms NOT balanced |
Need 1 more O atom on the left hand side of the equation.
1 atom of O is half an oxygen molecule (½O2)
Add ½ to the number of O2 molecules on the left hand side, that is, 1 + ½ = 1½ or 3/2 |
|
C2H5OH(l) |
+ |
1½O2(g) |
→ |
C(s) |
+ |
CO(g) |
+ |
3H2O(g) |
|
No. O atoms : |
1 |
+ |
(1½x2=3) |
= |
|
|
1 |
+ |
3x1 |
O atoms balanced |
- The balanced chemical equation for the incomplete combustion of methane gas in this experiment is (1):
C2H5OH(l) + 3/2O2(g) → C(s) + CO(g) + 3H2O(g)