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Identifying cis-trans Isomers in Alkene Molecules
Cis-trans isomers occur if there is:
- restricted rotation, or rigidity, as in the presence of a C=C bond
AND
- 2 different groups on the left-hand side of the C=C bond and 2 different groups on the right-hand side of the C=C bond.
Identifying cis-trans Isomers Example: 1,2-dibromoethane
Will 1,2-dibromoethane have both cis and trans isomers?
First, we need to draw the possible structures for this molecule:
but, because the carbon-carbon single bond, C-C, is NOT rigid, there is rotation around the C-C bond and in reality all of these possible structures exist in dynamic equilibrium with each other:
since none of these structures exist permanently, we can not refer to cis and trans isomers of 1,2-dibromoethane.
Only a molecule that contains rigidity, a C=C for example, can display cis-trans isomerism.
Identifying cis-trans Isomers Example: 1,1,2-tribromoethene
Will 1,1,2-tribromoethene have both cis and trans isomers?
First, draw the possible structures for this molecule:
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Rotating the molecule 180° in space makes the first 2 structures identical. |
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Rotating the molecule 180° in space makes the second 2 structures identical. |
rotating this molecule 180° in space |
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turns it into this molecule |
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so all 4 of the structures we have drawn are actually exactly the same! |
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1,1,2-dibromoethene does NOT display cis-trans isomerism.
Only a molecule with rigidity AND 2 different groups on the left-hand side of the C=C and 2 different groups on the right-hand side of the C=C can display cis-trans isomerism.
Identifying cis-trans Isomers Example: 1,2-dibromoethene
Will 1,2-dibromoethene have both cis and trans isomers?
First, draw the possible structures for this molecule :
if we rotate the whole molecule in space, we end up with only two different structures:
2 identical structures: both Br's on same side of the double bond |
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2 identical structures: Br's on different sides of the double bond |
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cis-isomer |
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trans-isomer |
because the C=C is rigid, you can't rotate the carbon atoms around the double bond.
You can NOT turn a cis-isomer into a trans-isomer because you can't rotate the carbon atoms around the double bond.
So these two structures, the cis-isomer and the trans-isomer, are NOT in dynamic equilibrium with each other and they are permanently different.
1,2-dibromoethene does display cis-trans isomerism because:
- 1,2-dibromoethene has rigidity: a C=C
- there are 2 different groups on the left-hand side of the C=C (an H and a Br)
and
2 different groups on the right-hand side of the C=C (an H and a Br)